check the picture below.
recall that in a rhombus, both diagonals bisect each other, namely cut each other in equal halves and at right-angles, so we end up with 4 right-triangles.
now, the sides in a rhombus are all equal, thus the perimeter is 13+13+13+13.
Answer:
-23
Step-by-step explanation:
j(2) = -2(2)
j(2) = -4
h(-4) = 5(-4) -3
h(-4) =-23
|4| = |7|
this is the answer of this question
