Answer: 2.28%
Step-by-step explanation:
Given: An airport find that at the present time, the mean noise level is 103 decibels and the standard deviation is 5.4 decibels.
The distribution of noise levels(x) for all jets during takeoff over the neighborhood has a normal distribution.
The probability that jets have a noise level less than 92.2 decibels when taking off over this neighborhood will be :-
Hence, the percent of these jets have a noise level less than 92.2 decibels when taking off over this neighborhood = 2.28%
Answer:
The minimum sample size to have this margin of error is n = 897.
Step-by-step explanation:
We have to estimate a parameter with a confidence interval. The confidence level is 95% and the margin of error is 0.5 days.
The population standard deviation is 7.64 days.
The critical value of z for a 95% confidence interval is z=1.96.
We have to calculate the minimum sample size.
To do that, we use the margin of error formula in function of n:
The minimum sample size to have this margin of error is n = 897.
Answer:
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Step-by-step explanation:
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Answer:
Step-by-step explanation:
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