Answer:
C
Step-by-step explanation:
V=4
/3πr3
3000=1 1/3*3.14*r*r*r
3000=4.18666667*r*r*r
716.560509=
Cube root the number
8.94851471456=r
TSA=4

TSA=4*3.14*8.94851471456*8.94851471456
TSA=1006.26
Since we used different numbers for pi and I rounded our answer will be different but the answer is C
Answer:
U = 5
S = 4
1.) P(X>x) = 0.5
Prob = 1-0.5 = 0.5
We have z = 0, that is the z score with the probability of 0.5
X = u + z(s)
= 5+0*4
= 5
2.) 1-0.95 = 0.05
Z score having this probability
Z = -1.64
X = 5-1.64*4
= 5-6.56
= -1.56
3.) P(z<1.0) - p(X<x) = 0.2
0.841345-0.2 = .641345
We find the z score given this probability
Z= 0.36
X = 5+0.36*4
= 5+1.44
= 6.44
4.) P(X<x)-P(Z<-.5)
0.95 = p(X<x)-0.308538
p(X<x) = 0.308538 + 0.95
= 1.258538
There is no x value here, given that the probability is more than 1.
5. 1-0.99/2 = 0.005
We get the z score value
= -2.58
U - 5 = 5-5 = 0
-x = 0-2.58(4)
X = 10.32
Answer:
a). 0.294
b) 0.11
Step-by-step explanation:
From the given information:
the probability of the low risk = 0.60
the probability of the high risk = 0.40
let
represent no claim
let
represent 1 claim
let
represent 2 claim :
For low risk;
so,
= (0.80 * 0.60 = 0.48),
= (0.15* 0.60=0.09),
= (0.05 * 0.60=0.03)
For high risk:
= (0.50 * 0.40 = 0.2),
= (0.30 * 0.40 = 0.12) ,
= ( 0.20 * 0.40 = 0.08)
Therefore:
a), the probability that a randomly selected policyholder is high-risk and filed no claims can be computed as:




b) What is the probability that a randomly selected policyholder filed two claims?
the probability that a randomly selected policyholder be filled with two claims = 0.03 + 0.08
= 0.11
Disjunction!
explanation: correct on edge2021