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mario62 [17]
3 years ago
9

Simplify the complex number √-16+8.

Mathematics
1 answer:
cestrela7 [59]3 years ago
3 0

Answer:

\sqrt{-16} +8

=4i+8

<u>OAmalOHopeO</u>

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20 students

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Strawberries cost $2 per pound. Kate buys 5 pounds and gets 20% discount on the total cost. How much does Kate pay for the straw
Tema [17]

The total cost without the discount is given by:

C = (2) * (5)\\C = 10$

Then, to find the discounted amount, we make the following rule of three:

10 $ ------------------> 100%

x ----------------------> 20%

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x = (\frac{20}{100}) * (10)\\x = 2

Then, the cost of the Strawberries with the discount is:

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Given f(x) = (lnx)^3 find the line tangent to f at x = 3
kirill [66]
Explanation

We must the tangent line at x = 3 of the function:

f(x)=(\ln x)^3.

The tangent line is given by:

y=m*(x-h)+k.

Where:

• m is the slope of the tangent line of f(x) at x = h,

,

• k = f(h) is the value of the function at x = h.

In this case, we have h = 3.

1) First, we compute the derivative of f(x):

f^{\prime}(x)=\frac{d}{dx}((\ln x)^3)=3*(\ln x)^2*\frac{d}{dx}(\ln x)=3*(\ln x)^2*\frac{1}{x}=\frac{3(\ln x)^2}{x}.

2) By evaluating the result of f'(x) at x = h = 3, we get:

m=f^{\prime}(3)=\frac{3}{3}*(\ln3)^2=(\ln3)^2.

3) The value of k is:

k=f(3)=(\ln3)^3

4) Replacing the values of m, h and k in the general equation of the tangent line, we get:

y=(\ln3)^2*(x-3)+(\ln3)^3.

Plotting the function f(x) and the tangent line we verify that our result is correct:

Answer

The equation of the tangent line to f(x) and x = 3 is:

y=(\ln3)^2*(x-3)+(\ln3)^3

6 0
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