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3 years ago

Solve the equation. Check the solution -4/x+1 = -1/x+5

Mathematics

2 answers:

Sveta_85 [38]3 years ago

7 0

Answer:

The correct answer is x=0.75

Step-by-step explanation:

-4/x+1 = -1/x+5

1/x-4/x = 5-1

1/x(1-4) = 4

-3 1/x=4

-3/x=4

x=-3/4

x=-0.75

Check

(-4/-0.75)+1=(-1/-0.75)+5

6,33=6,33

boyakko [2]3 years ago

4 0

The answer to this equation is x= -19/3

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Rock-music sales represented 24.8% of the total music sales in 2000. By 2007, rock-music sales represented 32.4% of the total mu

baherus [9]

Answer:

Unit Rate of Change = 1.27%

Step-by-step explanation:

In 2000, t=1 and Total Music sales = 24.8%

In 2007, t=7 and Total Music sales = 32.4%

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The Unit Rate of Change is 1.27% and it means that the Total Music Sales Increased by approximately 1.27% every year.

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3 years ago

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Free_Kalibri [48]

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3 years ago

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3 years ago

Multiply? I don't know how to do this o.o<br><br> (X+4√2) (x-4√2) (x-3i)

Korolek [52]

Answer:

$x^{3} -(3i) \; x^{2} -32x + 96 i$ .

Step-by-step explanation:

Notice that the first two factors are in the form $(x-a)(x+a)$ , which is equal to $(x^{2} - a^{2})$ . Start by combining and expanding these two factors:

Let $a = 4\sqrt{2}$ .

$a^{2} = 16 \times 2 = 32$ .

$(x + a) (x - a) = x^{2} - a^{2} = x^{2} -32$ .

This expression can now be expressed as $(x^{2} - 32)(x - 3i)$ . $i$ stands the unit imaginary number, where $i^{2} = -1$ . Unless $i$ is raised to a certain power other than $1$ , it can be treated just like a constant.

Expand this expression using FOIL:

$\begin{aligned}&(x^{2} - 32)(x - 3i)\\=&\underbrace{x^{2}\cdot x}_{\verb!F!} +\underbrace{(x^{2})(-3i)}_{\verb!O!} + \underbrace{(-32)x}_{\verb!I!} + \underbrace{(-32)(-3i)}_{\verb!L!}\\=& x^{3} -(3i)x^{2}-32x + 96i \end{aligned}$ .

6 0

2 years ago

What is the approximate solution to this equation?

Nookie1986 [14]

Answer:

C. x ≈ 0.28

Step-by-step explanation:

A graphing calculator solution is attached. It shows ...

x ≈ 0.28

You can divide both sides of the given equation by 5, then take natural logs and divide by 5 again.

5e^(5x) = 20 . . . . . . given

e^(5x) = 4 . . . . . . . . divide by 5

5x = ln(4) . . . . . . . . take natural logs

x = ln(4)/5 . . . . . . . divide by 5

x ≈ 0.277259 ≈ 0.28

7 0

2 years ago