Which expression represents the greatest common factor (GCF) of 48 and 136?

Mathematics

2 answers:

Romashka-Z-Leto [24]3 years ago

7 0

Answer:

Step-by-step explanation:

C and D dont go into 48 AND 136 evenly. B is the largest one there that goes into both 48 AND 136.

ta-da! :P

Lina20 [59]3 years ago

3 0

The answer is B

2 x 2 = 4

4 x 2 = 8

8 x 6 = 48

8 x 17 = 136

why isn't it C or D?

For C, 8 x 3 = 24 (throwing the 8 in there because the expression is the same as B).

24 x 2 = 48, but 24 x 5 = 120 and 24 x 6 = 144.

It's also the same reason why it's not D, except that the expression goes WAY into the 400's

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1. Find the derivative with respect to x of x +1/x from first principle. <br>

Murrr4er [49]

If you mean $f(x)=x+\frac1x$ , then the derivative is

$\displaystyle f'(x) = \lim_{h\to0} \frac{\left(x+h+\frac1{x+h}\right) - \left(x+\frac1x\right)}h \\\\ = \lim_{h\to0} \frac{(x+h)-x}h + \lim_{h\to0} \frac{\frac1{x+h} - \frac1x}h \\\\ = \lim_{h\to0} \frac hh + \lim_{h\to0} \frac{x-(x+h)}{hx(x+h)} \\\\ = \lim_{h\to0} 1 - \lim_{h\to0} \frac h{hx(x+h)} \\\\ = 1 - \lim_{h\to0} \frac1{x(x+h)} \\\\ = \boxed{1 - \frac1{x^2}}$

If you mean $f(x) = \frac{x+1}x = 1 + \frac1x$ , we know from above that

$\displaystyle \left(\frac1x\right)' = \lim_{h\to0} \frac{\frac1{x+h}-\frac1x}h = -\frac1{x^2}$

which leaves the constant term, whose derivative is

$\displaystyle (1)' = \lim_{h\to0}\frac{1 - 1}h = 0$

and so

$f'(x) = -\dfrac1{x^2}$

6 0

2 years ago

I need help plssss! Help me quick i need the answer plss and thank you!

harkovskaia [24]

Answer:

40%

Step-by-step explanation:

So, there are 60 students for B. So, what I did was add all the students to get 150. Then I divided 60 by 150 (60/150) to get 0.4. 0.4 * 100 is 40 which is the percent. Hope this helps.

7 0

2 years ago

Factor the expression completely <br> 8y-36

Shtirlitz [24]

Answer:

4(2y - 9)

Step-by-step explanation:

$8y - 36 \\ = 4(2y - 9) \\$