Ask question

Ask question

All categories

3 years ago

9

Can you solve number 74 plzzzzzzzzzzzzzzzzzzz

1 answer:

Mila [183]3 years ago

3 0

The answer would be graph b.
It would be graph b because the point would be five to the left(West) and two down(South).

You might be interested in

The larger of two numbers is 1 less than 3 times the smaller. their sum is 63. find the numbers

dybincka [34]

Your answer would be 5 and 2 :)

7 0

3 years ago

Read 2 more answers

Number 13 explain......

Marat540 [252]

The slope is 2 and the equation of the line is y = mx+b with m =2

Then the equation becomes: y = 2x+b. How to calculate b?
Since this line passes through the point (-3 , 4), we replace x with -3 and y=4

4= 2.(-3) + b
4 = - 6 + b
and b= 10. The final equation is : y = 2x + 10 (answer a)

3 0

3 years ago

On a coordinate plane, the segment with endpoints (10, 40) and (70, 120) is

OlgaM077 [116]

Answer:

The length of the resulting segment is 500.

Step-by-step explanation:

Vectorially speaking, the dilation is defined by following operation:

$P'(x,y) = O(x,y) + k\cdot [P(x,y)-O(x,y)]$ (1)

Where:

$O(x,y)$ - Center of dilation.

$P(x,y)$ - Original point.

$k$ - Scale factor.

$P'(x,y)$ - Dilated point.

First, we proceed to determine the coordinates of the dilated segment:

( $P(x,y) = (10, 40)$ , $Q(x,y) = (70, 120)$ , $O(x,y) = (0,0)$ , $k = 5$ )

$P'(x,y) = O(x,y) + k\cdot [P(x,y)-O(x,y)]$

$P(x,y) = (0,0) +5\cdot [(10,40)-(0,0)]$

$P'(x,y) = (50,200)$

$Q'(x,y) = O(x,y) + k\cdot [Q(x,y)-O(x,y)]$

$Q' (x,y) = (0,0) +5\cdot [(70,120)-(0,0)]$

$Q'(x,y) = (350, 600)$

Then, the length of the resulting segment is determined by following Pythagorean identity:

$l_{P'Q'} = \sqrt{(350-50)^{2}+(600-200)^{2}}$

$l_{P'Q'} = 500$

The length of the resulting segment is 500.

3 0

3 years ago

Stevie can refinish a driveway in 4 hours. Ray can refinish the same driveway in 3 hours. Princess can refinish the same drivewa

ch4aika [34]

Answer: 45 because 4+3+2=9 and 9x5=45

5 0

3 years ago

I need help solving this. |x−4| if x>4. You have to write the expression without using the absolute value sign.

labwork [276]

<h3>Answer: x-4</h3>

We simply drop the absolute value signs and write whatever is inside

This is because |x-4| is really composed of two equations and it depends on what x is

If x < 4, then we use -(x-4) or -x+4

If x >= 4, then we use x-4

This is from the idea that |x| breaks down into this piecewise function

$|x| = \begin{cases}x \text{ if } x \ge 0 \\ -x \text{ if } x < 0\end{cases}$

Replace every x with x-4

$|x-4| = \begin{cases}x-4 \text{ if } x-4 \ge 0 \\ -(x-4) \text{ if } x-4 < 0\end{cases}$

Then for each inequality, you would solve for x to get the following

$|x-4| = \begin{cases}x-4 \text{ if } x \ge 4 \\ -(x-4) \text{ if } x < 4\end{cases}$

which is the same as

$|x-4| = \begin{cases}x-4 \text{ if } x \ge 4 \\ -x+4 \text{ if } x < 4\end{cases}$

7 0

3 years ago