First one is y=4x and the second one is y=2x
Answer:
AC=9 cm
ABC is not a right angled triangle
Step-by-step explanation:
AB=8cm
BC=5cm
22=AB+BC+AC
AC=22-8-5
AC=9
since AC is the longest,
using Pythagoras theorem
AC^2=BC^2+AB^2
9^2=8^2+5^2
81=64+25
81=89
therefore, it is not a right angled triangle
Answer:4 and 5
Step-by-step explanation:
√(20) is approximately 4.5 so it is between 4 and 5
First, we need to find the base. To do so, we will need to use the Pythagorean Theorem on one of the smaller triangles to solve for its unknown side. Then, we can double the base of the one to find the base of the whole.
Pythagorean Theorem: a^2 + b^2 = c^2
(12)^2 + b^2 = (16)^2
144 + b^2 = 256
b^2 = 112
b = 
b = 
total base = 2 x
= 
Second, we can find the area. The formula for the area of a triangle is A = 1/2 x base x height.
A = 1/2 x
x 12
A =
x 12
A =
units^2
Third, we can find the perimeter. The perimeter is the sum of all of the exterior sides.
P = 16 + 16 +
P = 32 +
units
Hope this helps!! :)