All categories

3 years ago

URGENT!! DESPERATE!! GEOMETRY REFLECTIONS!!! PLEASE INCLUDE EXPLANATION BOGUS ANSWERS WILL BE REPORTED

Mathematics

1 answer:

serious [3.7K]3 years ago

3 0

When we reflect a point across y=x, the x and y coordinates switch out , that is (x,y) becomes (y,x) . SO for point (1,2), on reflection across y=x, (1,2) becomes (2,1) . And when we do reflection across y=-x, (x,y) becomes (-y,-x). Therefore point (2,1) on reflection across y=-x becomes(-1,-2) .

So the final answer is (-1,-2) .

You might be interested in

Please help me y’all!!!!

DerKrebs [107]

Step-by-step explanation:

a^2 + 2(b - 6) - 17. a = -7 b = 2

= (-7)^2 - 2(2 - 6) - 17

= 49 - 4 + 12 - 17

= 40

6 0

2 years ago

Which is the length of the arc MPN expressed in terms of pie?

Luba_88 [7]

Answer:

\frac{79}{9} \pi

Step-by-step explanation:

3 0

2 years ago

Vineet solved a system of equations by substitution. In his work, he substituted an expression for one of the variables and solv

Eddi Din [679]

He can conclude that the system of equations has no solution since one equation in it always results with false equivalency.

Hope this helps.

r3t40

3 0

3 years ago

Read 2 more answers

If Upper X overbar equals 62, Upper S equals 8, and n equals 36, and assuming that the population is normally distributed, c

marishachu [46]

Answer:

The 99% confidence interval would be given by (58.373;65.627)

We are 99% confident that the true mean for the variable of interest is between 58.373 and 65.627.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=62$ represent the sample mean

$\mu$ population mean (variable of interest)

s=8 represent the sample standard deviation

n=36 represent the sample size

Part a: Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=36-1=35$

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,35)".And we see that $t_{\alpha/2}=2.72$