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4 years ago

Do I have to subtract or what? Please help.

Mathematics

1 answer:

KatRina [158]4 years ago

5 0

The maximum drop of Colossus is 185ft less than the maximum drop of Millennium Force.

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How many real solutions does the system have?<br><br><br> {y=−3x−3y=x2−3x+5

Daniel [21]

The answer is 0
I took the test and got it right i hope this helps someone

5 0

4 years ago

Read 2 more answers

Which one should I choose.

Mice21 [21]

Answer: 9

54 ÷ 2

3x = 27

x = 9

7 0

3 years ago

Ten samples of a process measuring the number of returns per 100 receipts were taken for a local retail store. The number of ret

Tatiana [17]

Answer:

0.0273

Step-by-step explanation:

np n

10 100

9 100

11 100

7 100

3 100

12 100

8 100

4 100

6 100

11 100

pbar=sumnp/sumn

pbar=10+9+11+7+3+12+8+4+6+11/10+10+10+10+10+10+10+10+10+10

pbar=81/1000

pbar=0.081

nbar=sumn/k=1000/10=100

$Standard deviation for pbar chart=\sqrt{\frac{pbar(1-pbar)}{nbar} }$

$Standard deviation for pbar chart=\sqrt{\frac{0.081(0.919)}{100} }$

$Standard deviation for pbar chart=\sqrt{\frac{0.0744}{100} }$

$Standard deviation for pbar chart=\sqrt{0.0007444 }$

Standard deviation for p-chart=0.0273

3 0

3 years ago

PLEASE HELP ME!!!!! THIS IS TIMED PLEASE HELP!!

antiseptic1488 [7]

Answer:

20 I think I hope it is correct

8 0

3 years ago

Read 2 more answers

A worker at a landscape design center uses a machine to fill bags with potting soil. Assume that the quantity put in each bag fo

defon

Answer:

a) The expected value is given by:

$E(X) =\frac{a+b}{2}= \frac{10+12}{2}= 11$

The variance is given by:

$Var(X) = \frac{(b-a)^2}{12}= \frac{(12-10)^2}{12}= 0.3333$

And the standard deviation is just the square root of the variance and we got:

$Sd(x) = \sqrt{0.3333}= 0.5774$

b) $P(X$

And we can use the cumulative distribution function given by:

$F(x) = \frac{x-a}{b-a}, a \leq x \leq b$

And using this function we got:

$P(X$

c) $P(X>10.5)$

And using the complement rule and the cumulative distribution function we got:

$P(X>10.5)= 1-P(X$

Step-by-step explanation:

For this case we define the random variable X=quantity put in each bag , and we know that the distribution for X is given by:

$X \sim Unif (a= 10, b =12)$

Part a

The expected value is given by:

$E(X) =\frac{a+b}{2}= \frac{10+12}{2}= 11$

The variance is given by:

$Var(X) = \frac{(b-a)^2}{12}= \frac{(12-10)^2}{12}= 0.3333$

And the standard deviation is just the square root of the variance and we got:

$Sd(x) = \sqrt{0.3333}= 0.5774$

Part b

For this case we want this probability:

$P(X$

And we can use the cumulative distribution function given by:

$F(x) = \frac{x-a}{b-a}, a \leq x \leq b$

And using this function we got:

$P(X$

Part c

For this case we want this probability:

$P(X>10.5)$

And using the complement rule and the cumulative distribution function we got:

$P(X>10.5)= 1-P(X$

3 0

4 years ago