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artcher [175]
3 years ago
7

At a wedding reception, the caterer served fishing chicken. The fish dinner cost $12 per person in the chicken cost $9 per perso

n. The caterer charged 2544 total for the dinner. If 232 people went to the reception, how many people had fish how many had chicken.
Mathematics
1 answer:
maw [93]3 years ago
5 0

Answer:

80 persons haf fish and 152 persons had chicken

Step-by-step explanation:

Given data

let the number of persons that had fish be x and chicken be y

so

12x+9y=2544------------------1

x+y= 232------------------------2

from 2

x= 232-y

substitute the value of x in 1

12(232-y)+9y=2544

2784-12y+9y=2544

2784-3y=2544

3y= 2784-2544

3y=240

y= 240/3

y=80

put y= 80 in 2

x+80= 232

x= 232-80

x=152

Hence 80 persons haf fish and 152 persons had chicken

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