At a wedding reception, the caterer served fishing chicken. The fish dinner cost $12 per person in the chicken cost $9 per perso
n. The caterer charged 2544 total for the dinner. If 232 people went to the reception, how many people had fish how many had chicken.
1 answer:
Answer:
80 persons haf fish and 152 persons had chicken
Step-by-step explanation:
Given data
let the number of persons that had fish be x and chicken be y
so
12x+9y=2544------------------1
x+y= 232------------------------2
from 2
x= 232-y
substitute the value of x in 1
12(232-y)+9y=2544
2784-12y+9y=2544
2784-3y=2544
3y= 2784-2544
3y=240
y= 240/3
y=80
put y= 80 in 2
x+80= 232
x= 232-80
x=152
Hence 80 persons haf fish and 152 persons had chicken
You might be interested in
Answer: all of them are x,y
Step-by-step explanation:
Answer:
18
Step-by-step explanation:
Let the unknown number be = x
Then,
x + 16 = 34
=> x = 34 - 16
=> x = 18 (Ans)
Answer:
Step-by-step explanation:
5+1=6
5-1=4
4/6 = 60
6/6 = ?
6/6 x 60 x 6/4
= 75 people
sorry if I'm wrong. I got confused because you put 56+3 twice.×= 63
56+3=59=x-4 (this is with subtraction sign)
I didnt know if that a subtracting or negative so here both
56+3=x-4 (this is with the negative sign)
x= -14.75
Answer:
57.6
Step-by-step explanation: