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Misha Larkins [42]

3 years ago

5

PLEASE!!! HELP GIVING BRAINLIEST

2 answers:

kirill115 [55]3 years ago

3 0

The first one is d 4.5.t

coldgirl [10]3 years ago

3 0

For problem 5: A, C, and E

1b + 1b + 1b + 1b is 4b
2b + 2b is 4b
b/ 1/4 = 1b/1 x 4/1 = 4b/1 = 4b

For Problem 4:

A. 35 x 91 = 3185
35 x 89 = 3115
3185 - 3115 = 70

B. 22 x 87 = 1914
22 x 13 = 286
1914 + 286 = 2200

C. 9/11 x 7/10 = 63/110
9/11 x 3/10 = 27/110
63/110 - 27/110 = 36/110 / 2 = 18/55

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Pls help !! will give brainilest

Brut [27]

It’s a linear function so,

y = mx+b

b is 0.

m is rise/run, which is 6/3, which is 2.

so

y=2x

hope this helps!

5 0

3 years ago

Read 2 more answers

During a sale, thetc price of a sweater was changed from $20 to $16. What was the percent of decrease in the price of the sweate

Shalnov [3]

Percent change=change/original times 100

change=20-16=4
original=20

change=4/20 times 100=0.2 times 100=20

answer is 20%

3 0

3 years ago

Read 2 more answers

The label on the car's antifreeze container claims to protect the car between −40°C and 140°C. To covert Celsius temperature to

telo118 [61]

Answer:

$-40$

Step-by-step explanation:

We must convert the given temperatures from degrees Celsius to degrees Fahrenheit

The formula is:

$C=\frac{5}{9}(F-32)$

Where C is the temperature in degrees Celsius and F is the temperature in degrees Fahrenheit

Then we must replace the temperature in degrees Celsius and solve the equation for F

$C*\frac{9}{5}=(F-32)$

$F=C*\frac{9}{5}+32$

$F=(-40)*\frac{9}{5}+32$

$F=-40\ \°F$

$F=(140)*\frac{9}{5}+32$

$F=284\ \°F$

The Fahrenheit temperature range in which the antifreeze protects the car is:

$-40$

5 0

3 years ago

ecn 221 The sodium content of a popular sports drink is listed as 206 mg in a 32-oz bottle. Analysis of 14 bottles indicates a s

spayn [35]

Answer:

$H_{0}: \mu = 206\text{ mg}\\H_A: \mu \neq 206\text{ mg}$

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 206 mg

Sample mean, $\bar{x}$ = 217.5 mg

Sample size, n = 14

Sample standard deviation, s = 14.9 mg

Claim:

The mean sodium content for the sports drink is not 206 mg. It is different than 206 mg.

Thus, we design the null and the alternate hypothesis

$H_{0}: \mu = 206\text{ mg}\\H_A: \mu \neq 206\text{ mg}$

We use two-tailed t test to perform this hypothesis.

3 0

3 years ago

Is this right please help!!

LenaWriter [7]

Answer:

....

Step-by-step explanation:

6 0

3 years ago