$The \ \mathbf{distance} \ d \ between \ the \ \mathbf{points} \ (x_{1},y_{1}) \ and \ (x_{2},y_{2}) \ in \ the \ plane \ is:\\ \\ d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

As in the statement:

<em>The distance form</em> $(0,0)$ to $(0,2)$ is $\sqrt{(0-0)^2+(2-0)^2}=\sqrt{2^2}=2$ <em>whose justification is the </em><em>Distance Formula. </em>

<em />

Here in this statement the justification is also the Distance Fromula, so we take the distance from $(0,0) \ to \ (1,\sqrt{2})$ whose result is also 2 and is the radius of the circle.

3 0

2 years ago

Read 2 more answers

M is the midpoint of AB.<br> AM = = 4x - 8<br> MB =<br> 5x-3/3<br> Find x and AB

marusya05 [52]

X=-7 AB=-72

steps

since m is a midpoint, AM and MB are congruent so you set the two equations equal to each other, 4x-9=5x-3/3( is this a typo? bc 3/3 is 1)
subtract 4x from both sides m, -8=x-1
add 1 to both sides
x=-7

then plug -7 in for x 4(-7)-8=-36
since the two segments are congruent u do -36 x 2= -72

7 0

2 years ago

A shark weighs 405 kg and 68 grams a second shark weighs 324 kg and 75 g how much more does the first shark weigh in grams than

mariarad [96]

For this case we have to by definition:

1 kg equals 1000 grams

Shark 1:

405 kg and 68 grams

$405 kg * \frac {1000 g} {1kg} = 405,000 grams$

Thus, shark 1 weighs 405,068 grams.

Shark 2:

324 kg and 75 grams

$324 kg * \frac {1000 g} {1 kg} = 324,000 grams$

Thus, shark 2 weighs 324,075 grams.

Subtracting we have:

$405.068 grams-324.075 grams = 80.993 grams$

Thus, shark 1 weighs 80,993 grams more than the second.

Answer:

Shark 1 weighs 80,993 grams more than the second.

8 0

3 years ago