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2 years ago

If something cost $37.80, how many tens would you give?

Mathematics

1 answer:

Sophie [7]2 years ago

5 0

Answer:

4 tens

Step-by-step explanation:

3 tens would get you $30, which is $7.80 short. If you give 4 tens you are giving $40 which is 2.20 more than $37.80, which is okay as you can probably get change and it is the least amount of tens you can give to cover the cost.

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Is (x+5) A FACTOR OF f(x) = x3 − 4x2 + 3x + 7

AlekseyPX

Answer:

<u><em>(x+5) is not a factor of f(x)</em></u>

Step-by-step explanation:

Step 1 : we solve the equation x +5 = 0

x + 5 = 0 then x = -5

Step 2: we plug in -5 into f(x)

If we get zero then x+5 is a factor of f(x)

If we get a number other than zero then x+5 is not a factor of f(x)

Calculation:

f(-5) = (-5)³ − 4(-5)² + 3(-5) + 7 = - 233

Since we got -233 and not 0

Therefore ,(x+5) is not a factor of f(x)

8 0

2 years ago

Read 2 more answers

What is 29 2/19 plus 5 1/2?

boyakko [2]

29 2/19 + 5 1/2 = 29 4/38 + 5 14/38 = 34 18/38 = 34 9/19

7 0

3 years ago

Describe the steps you would use to solve the equation 4x + 7 = 15

choli [55]

i would subtract 7 and divide by 4;

4x + 7 = 15

4x = 8

x = 2

8 0

3 years ago

Read 2 more answers

What two numbers add up to 6 and multiply to 12?

GuDViN [60]

Erm

x+y=6
xy=12

x+y=6
y=6-x
sub back

xy=12
x(6-x)=12
6x-x^2=12
x^2-6x=-12
x^2-6x+12=0
quadratic formula
for
ax²+bx+c=0
$x= \frac{-b+/- \sqrt{b^2-4ac} }{2a}$

for
x²-6x+12=0
a=1
b=-6
c=12
and remember that √-1=i

$x= \frac{-(-6)+/- \sqrt{(-6)^2-4(1)(12)} }{2(1)}$
$x= \frac{6+/- \sqrt{36-48} }{2}$
$x= \frac{6+/- \sqrt{-12} }{2}$
$x= \frac{6+/- (\sqrt{-1})(\sqrt{12}) }{2}$
$x= \frac{6+/- (i)(2\sqrt{3}) }{2}$
$x= \frac{6+/- 2i\sqrt{3} }{2}$
x=3+/-i√3

the numbers are 3+i√3 and 3-i√3
no real numbers tho

7 0

3 years ago

I need help with an algebra assignment right away!

Georgia [21]

So remember that slope-intercept form is y = mx+b (m = slope, b = y-intercept) and standard form is ax+by = c. (a and b are coefficients and c is the constant)

Starting with the first question: 9x + 2y = 6

Firstly, subtract 9x on both sides: 2y = -9x + 6

Next, divide both sides by 2, and your equation will be y = -4.5x + 3

Now with the next equation: y - 3 = 4(x + 1)

Firstly, foil 4(x + 1): y - 3 = 4x + 4

Next, subtract y on both sides: -3 = 4x - y + 4

Next, subtract 4 on both sides, and your answer will be: -7 = 4x - y

Next equation: y + 7 = -2(x - 3)

Firstly, foil -2(x - 3): y + 7 = -2x + 6

Next, subtract 7 on both sides of the equation, and your answer will be: y = -2x - 1

Next: y - 5 = 3(x - 2) (part a)

Firstly, foil 3(x - 2): y - 5 = 3x - 6

Next, add 5 on both sides, and your equation is: y = 3x - 1

Next, y - 5 = 3(x - 2) (part b)

Firstly, foil 3(x - 2): y - 5 = 3x - 6

Next, subtract y on both sides of the equations: -5 = 3x - y - 6

Next, add 6 on both sides of the equation, and your answer will be: 1 = 3x - y

4 0

3 years ago