Answer:
3(3x + 5)
Step-by-step explanation:
x + 8x + 15 Combine liked terms
9x + 15
GCF: 3
3(3x +5) Factor
F(3) = 16, you simply plug in 3 for x to find the answer.
9514 1404 393
Answer:
- 85°
- 60°
Step-by-step explanation:
1. Angle JKL is half the measure of the intercepted arc JK.
(1/2)JK = 1/2(360° -190°) = (1/2)(170°) = 85°
angle JKL is 85°
__
2. The angle between tangents is the supplement of the intercepted arc.
angle JKL = 180° -(360° -240°)
angle JKL = 60°
The answer to this question will depend on the function f itself. Basically you will find the height in meters above the ground of the bird when it jumped when the time t=0s. This is substsitute every t in the function for a value of zero and that way you will get the bird's height at the time it jumped. If you were given a graph for this function, you can find the y-intercept of the graph and that will be the answer as well. The question could be written like this:
A baby bird jumps from a tree branch and flutters to the ground. The function "
" models the bird's height (in meters) above the ground as a function of time (in seconds) after jumping. What is bird's height above the ground when it jumped.
Answer:
25m
Step-by-step explanation:
Once your function is given, you can substitute t=0 since 0s is the time measured at the moment the bird jumped. So our function will be:
So the height of the bird above the ground when it jumped is 25m in this particular function.
Answer:
probability that the other side is colored black if the upper side of the chosen card is colored red = 1/3
Step-by-step explanation:
First of all;
Let B1 be the event that the card with two red sides is selected
Let B2 be the event that the
card with two black sides is selected
Let B3 be the event that the card with one red side and one black side is
selected
Let A be the event that the upper side of the selected card (when put down on the ground)
is red.
Now, from the question;
P(B3) = ⅓
P(A|B3) = ½
P(B1) = ⅓
P(A|B1) = 1
P(B2) = ⅓
P(A|B2)) = 0
(P(B3) = ⅓
P(A|B3) = ½
Now, we want to find the probability that the other side is colored black if the upper side of the chosen card is colored red. This probability is; P(B3|A). Thus, from the Bayes’ formula, it follows that;
P(B3|A) = [P(B3)•P(A|B3)]/[(P(B1)•P(A|B1)) + (P(B2)•P(A|B2)) + (P(B3)•P(A|B3))]
Thus;
P(B3|A) = [⅓×½]/[(⅓×1) + (⅓•0) + (⅓×½)]
P(B3|A) = (1/6)/(⅓ + 0 + 1/6)
P(B3|A) = (1/6)/(1/2)
P(B3|A) = 1/3
