Step-by-step explanation: The great thing about the y-intercept is that it is a point, but it always has an x-coordinate of zero.
So when we are given two points, you can easily find the slope of the points by taking the second y coordinate minus the first y coordinate and dividing it by the second x coordinate minus the first x coordinate.
That value will give you your slope or your steepness of the line.
The y-intercept is easy since you're already given it so just add or subtract it from your slope to write the equation of the line.
Answer:
a) 20 minutes
b) 36 km/h
c) 33.67 km
d) continuous driving without any stationary phases.
Step-by-step explanation:
by the way, speed is specified in distance per time unit. in your example as km/h. and that is how your write this.
not km/h¯¹. that would be wrong, as that would actually be km×h. but you can write e.g. km×h¯¹. that is the same as km/h.
between minutes 5 and 25 there is no progress in distance. so, for these 20 minutes the bus was stationary.
in the first 5 minutes the bus drove 7-4=3 km.
so, in 5 minutes 3 km. to determine the speed we need to calculate up to see, how many km would be have driven in a full hour (60 minutes). the same factor for the time has then to be applied also to the distance to keep the ratio unchanged.
5 × x = 60
x = 12
3 × 12 = 36
so, the speed in these first 5 minutes was 3 km/5 min.
or then in km/h : 36 km/h
between the minutes 25 and 45 the bus drove with a speed of 80km/h.
and the starting point there was at 7 km.
so, the bus drove s-7 km in 20 minutes.
as before, let's first find the scaling factor to deal with a full hour instead of only 20 minutes.
20 × x = 60
x = 3
as before : distance × scaling factor = distance for km/h
(s-7) × 3 = 80
3s - 21 = 80
3s = 101
s = 33.666666666... km
Multiply (h+3t= -10) to get 2h+6t=-20.
(<span>2h+6t=-20</span>) - (2h+t=-8) to get 5t=-28
therefore t=-5.6
put t into any equation. i.e (2h-t=-8) = 2h+5.6=-8
therefore 2h = -13.6
h=-6.8
Answer:
(0,5) and (10,0)
Step-by-step explanation:
The equation of the straight line is given by 2x + 4y = 20 .......... (1)
Now, point (0,5) satisfies the equation (1) as putting x = 0, we will get y = 5.
Now, point (0,10) does not satisfy the equation (1) as putiing x = 0, we get y = 5 ≠ 10
Again, point (1,2) does not satisfy the equation (1) as putiing x = 1, we get y = 4.5 ≠ 2
Now, point (1,4) does not satisfy the equation (1) as putiing x = 1, we get y = 4.5 ≠ 4
Again, point (5,0) does not satisfy the equation (1) as putiing y = 0, we get x = 10 ≠ 5
Finally, point (10,0) satisfies the equation (1) as putiing y = 0, we get x = 10 .
Therefore, only points (0,5) and (10,0) are on the graph of the line 2x + 4y = 20 (Answer)