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3 years ago

If f(1)=5 and f(3)=7 and f(8)= -10 what is f to the negative 1 power (5)

Mathematics

1 answer:

rosijanka [135]3 years ago

6 0

It’s f4=8 for the neg power

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The area of a circle is 616cm find the radius

Leokris [45]

<h3>Given :-</h3>

Area of Circle = 616 cm²

Radius of a circle = ?

<h3>Solution :-</h3>

☼︎ <u>Radius of the Circle</u>;

<h3>Using Formula:</h3>

$\\ \red\bigstar {\underline{\boxed{\color{springgreen}{\textsf{ \textbf{ \: Area \: of \: circle= \: \: π \: r \: ² \: }}}}}} \\\\$

<u>Putting values in the formula;</u>

$\\ \sf \implies \: Area \: = \: \pi \: r \: ^{2} \\$

$\\ \sf \implies \: 616 \: = \:\frac{22}{7} \times \: r \: ^{2} \\$

$\\ \sf \implies \: 616 \: \times \: \frac{7}{22} \: = \: \: r \: ^{2} \\$

$\\ \sf \implies \: \: \frac{ \: \: 4312 \: \: }{22} \: = \: \: r \: ^{2} \\$

$\\ \sf \implies \: \: \cancel{\frac{ \: \: 4312 \: \: }{22} }\: = \: \: r \: ^{2} \\$

$\\ \sf \implies \: \: \: 196 \: \: = \: \: r \: ^{2} \\$

$\\ \sf \implies \: \:r \: ^{2} = \: 196 \: \: \: \: \\$

$\\ \sf \implies \: \:r \: = \sqrt{ \: 196 \: } \\$

$\\ \bf \implies \: \:Radius \: = 14 \: cm \\$

henceforth, the Radius of a circle is 14 cm ...!!

6 0

1 year ago

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an airline experiences a no show rate of 6%. what is the maximum number of reservations that it could accept for a flight with a

Alborosie

168 passengers because 168*95%=159.6

Therefore 168 passengers would have to book the flight

7 0

3 years ago

How do you solve this?

maks197457 [2]

The answer is (x-5)(x-4)

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3 years ago

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Can anyone tell me what is 2/5 x 3/2 ?

Mars2501 [29]

Answer:

6/10

Step-by-step explanation:

2 × 3 = 6

5 × 2 = 10

6/10 = 3/5

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2 years ago

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Find the dicontinuities of the function.

elena-s [515]

Answer:

Step-by-step explanation:

I'm assuming you meant to type in

$f(x)=\frac{x^2+12x+27}{x^2+4x+3}$ because you can only have removable discontinuities where there is a rational (fraction) function. Begin by factoring both the numerator and denominator to

$f(x)=\frac{(x+3)(x+9)}{(x+1)(x+3)}$ and cancelling out like terms would have us eliminating the (x + 3). That is where there is a removable discontinuity. It leaves a hole. The other discontinuity, (x + 1) doesn't cancel out so it is a non-removable discontuinity, which is a vertical asymptote.

The removable discontinuity is at -3. There is no y value at x = -3 (remember there's only a hole here), because -3 causes the denominator to go to 0 and we all know that having a 0 in the denominator of a fraction is a big no-no!!!

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3 years ago