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likoan [24]
3 years ago
13

1/3 HB=T solve for B​

Mathematics
1 answer:
Mariana [72]3 years ago
3 0

Answer:

yes I agree B=3t/h

Step-by-step explanation:

hope this helps :)

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The value of n needed to make the equation true.<br> n+19=40
Schach [20]

Answer:

n = 21

Step-by-step explanation:

Given

n + 19 = 40 ( subtract 19 from both sides )

n = 40 - 19 = 21

6 0
3 years ago
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Julio bought 4 pounds of apples and one bag of oranges at the store. The apples cost $1.75 per pound and the bag of oranges cost
vaieri [72.5K]

Answer: $9.99

Step-by-step explanation:

There are 4 pounds of apples with each pound costing $1.75.

There is one bag of orange with a bag costing $2.99.

Total = (4 * 1.75) + 2.99

= 7 + 2.99

= $9.99

5 0
3 years ago
The variable Z is inversely proportional to X. When X is 6, Z has the value 2.
Vera_Pavlovna [14]
Inverse proportion is of the form:

y=k/x, in this case the variables are

z=k/x, and we are given the point (6,2) so we can solve for k

2=k/6

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z=12/x, so when x=13

z=12/13
6 0
3 years ago
If a fire is burning a building and it takes 2 hours to put it out using 2000 gal./min., what minimum diameter cylindrical tank
strojnjashka [21]

Answer:

The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.

Step-by-step explanation:

A gallon equals 0.134 cubic feet. First, we determine the amount of water (Q), measured in cubic feet, needed to put out the fire under the assumption that water is consumed at constant rate:

Q = \dot Q \cdot \Delta t (1)

Where:

\dot Q - Volume rate, measured in feet per minute.

\Delta t - Time, measured in minutes.

If we know that \dot Q = 2000\,\frac{gal}{min} and \Delta t = 120\,min, then the amount of water is:

Q = \left(2000\,\frac{gal}{min} \right)\cdot (120\,min) \cdot \left(0.134\,\frac{ft^{3}}{gal} \right)

Q = 32160\,ft^{3}

And the diameter of the cylindrical tank based on the capacity found above is determined by volume formula for a cylinder:

Q = \frac{\pi}{4}\cdot D^{2}\cdot h (2)

Where:

D - Diameter, measured in feet.

h - Height, measured in feet.

If we know that Q = 32160\,ft^{3} and h = 12\,ft, then the minimum diameter is:

D^{2} = \frac{4\cdot Q}{\pi\cdot h}

D = 2\cdot \sqrt{\frac{Q}{\pi\cdot h} }

D = 2\cdot \sqrt{\frac{32160\,ft^{3}}{\pi\cdot (12\,ft)} }

D \approx 58.415\,ft

The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.

8 0
3 years ago
4 9/10 divided by 2 3/5
lora16 [44]
<span>4 9/10 divided by 2 3/5

</span>4 9/10 = 49/10
2 3/5 = 13/5 

so
(49/10) / (13/5)
=49/10 * 5/13
= 49/26
or
= 1 23/26
8 0
3 years ago
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