You need to add more context im afriad
Question:
If a sample of 2 hammer is selected
(a) find the probability that all in the sample are defective.
(b) find the probability that none in the sample are defective.
Answer:
a
b
Step-by-step explanation:
Given
--- hammers
--- selection
This will be treated as selection without replacement. So, 1 will be subtracted from subsequent probabilities
Solving (a): Probability that both selection are defective.
For two selections, the probability that all are defective is:
Solving (b): Probability that none are defective.
The probability that a selection is not defective is:
For two selections, the probability that all are not defective is:
Answer:
I would help but I can't see the picture... sorry good luck
Step-by-step explanation:
To solve this polynomial equation, we will need to factor the left side.
On the left, we have a a trinomial in a special form that
can be factored as the product of two binomials.
The trinomial on the left can be factored which makes life easier.
This factors as (x + 11)(x - 2) = 0.
This means that either x + 11 = 0 or x - 2 = 0.
Solving each equation from here, we get x = -11 or x = 2.
So the solution is {-11, 2}.
Coterminal angles are angles in standard position with the same terminal side. For example, angles measuring 120° and – 240° are coterminal.