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pshichka [43]
3 years ago
13

Write an equation of the line in slope-intercept form.

Mathematics
2 answers:
Katena32 [7]3 years ago
6 0

Answer:

Ex-

y=3x+7

^y=Mx+b form^

NNADVOKAT [17]3 years ago
6 0
Yeah what they said lol
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the function t(n) 8n represents the number of tires t(n) that are needed for n trucks. if t(n)=200. what is the value of n?
mr_godi [17]

Step-by-step explanation:

if I understand correctly, then the function is

t(x) = 8x

now we know, that for a specific n

t(n) = 200

that means

200 = 8n

n = 200/8 = 25

the function tells us, that for 25 trucks we need 200 tires.

8 0
2 years ago
1.)12.5+(-31.5)=<br>2.)-31.91+(-16.7)=<br>3.)1/6+(-11/12)+2/3=<br>4.)29+(-15.7)+(-31.05)=
Xelga [282]
1. = Step 1. Simplify Brackets and you get 12.5 - 31.5 Step 2. Simplify and you get -19&#10; which is your answer.

2. = Step 1. Simplify Brackets and you get -31.91-16.7 Step 2. Simplify and you get -48.61

3. = Step 1. Simplify Brackets and you get \frac{1}{6} - \frac{11}{12} + \frac{2}{3} Step 2. Simplify and you get - \frac{1}{12}

4. Step 1. = Simplify Brackets and you get 29-15.7-31.05 Step 2. Simplify and you get -17.75
5 0
4 years ago
2.In quadratic equation ax2 + bx + c = 0, if discriminant is D= b2 - 4ac, then roots of the quadratic equation are
tino4ka555 [31]

Answer:

(2) Real and equal (i.e., repeated roots), if D = 0.

Step-by-step explanation:

.In a quadratic equation ax2 + bx + c = 0, if discriminant is D= b2 - 4ac, then roots of the quadratic equation are

Real and equal (i.e., repeated roots), if D = 0.

If the D > b² - 4ac then it's real and distinct.

3 0
3 years ago
I have to find the circumference of 15 cm​
Pie

Answer:

r = 2.39 and C=2πr=2·π·2.39≈14.99997

Step-by-step explanation:

Using the formula

C=2πr

Solving for r=C 2π=15

2·π≈2.38732

and then u round up the 7 told the 8 to go up.

2.39

7 0
3 years ago
2.375 in expanded form
kari74 [83]

Answer:

2375^-3

Step-by-step explanation:

Move the decimal place from 2.375 to the back of the number so it should look like this, 2375.

Than move the decimal place back to its original spot and count the amount of spaces you move. Remember, if you move forward, your exponent should be negative. For example, if the problem is 6.321, you would move the decimal place to the back like this, 6321. And then move it back to where it originally was, 6.321, the amount of spaces I moved was 3 spaces and I moved forward so It would be 6.321^-3

6 0
3 years ago
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