6.0⋅<span>102</span><span>kg m<span>−3</span></span>
Explanation:
In order to find the density of the bowling ball, <span>ρ
</span>, you must determine the mass one unit of volume of this bowling ball would have.
Notice that the problem provides you with the volume of the bowling ball expressed cubic meters, <span><span>m3</span>
</span>, which means that one unit of volume would be <span><span>1 m3</span>
</span>.
Now, you know that a volume of <span><span>0.0050 m3</span>
</span> has a mass of <span>3.0 kg
</span>. You can use this known proportion as a conversion factor to figure the mass of <span><span>1 m3</span>
</span>
<span><span>1<span>m3</span>⋅<span>3.0 kg<span>0.0050<span>m3</span></span></span>=600 kg</span>
</span>
So, you know that one unit of volume has a mass of <span>600 kg
</span>, which means that the bowling ball's density is equal to
<span><span><span>ρ=6.0⋅<span>102</span><span>kg m<span>−3</span></span></span><span>−−−−−−−−−−−−−−−−−</span></span>
</span>
The answer is rounded to two sig figs.
Answer:0.002
Step-by-step explanation:
Answer:
-1 and -30 -1+-30=-31
-2 and -15 -2+-15=-17
-3 and -10 -3+-10=-13
-5 and -6 -5+-6=-11
-6 and -5 -6+-5=-11
-10 and -3 -10+-3=-13
-15 and -2 -15+-2=-17
-30 and -1 -30+-1=-31
30 and 1 30+1=31
15 and 2 15+2=17
10 and 3 10+3=13
6 and 5 6+5=11
5 and 6 5+6=11
3 and 10 3+10=13
2 and 15 2+15=17
1 and 30 1+30=31
Step-by-step explanation:
A factor is a number that can be evenly divided by another number without a remainder or decimal. These numbers can all be divided by 30 without resulting in a remainder. After we find the corresponding factor (by dividing by 30), we add them in the resulting column.
Answer:
5
Step-by-step explanation:
Put 3 where x is and do the arithmetic.
f(x) = 2x -1
f(3) = 2·3 -1 = 6-1
f(3) = 5
PEMDAS
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction
Addition/subtraction as well as Multiplication/Division happen from left to right
