Answer:
![\sqrt[4]{2}^{3}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B2%7D%5E%7B3%7D)
Step-by-step explanation:
In order to find the circumference, we first need to find the radius. We have the area, so we can find the radius. We set up this equation:

We begin by dividing both sides by pi.
483.76 =

Next, we take the square root of both sides to get the radius.
r = 22.
Next, we plug this into the formula for the circumference, 2 pi r

So, the circumference of this circle is 138.23 units.
|x|∈{0,1,2,3,4}
x∈{-4,-3,-2,-1,0,1,2,3,4}
How to solve exponents:
Learn the correct words and vocabulary for exponent problems. When you have an exponent, like 2^{3}, you have two simple parts. The bottom number, here a 2, is the base. The number it is raised to, here a 3, is known as the exponent or power. If you are talking about 2^{3}, you would say it is "two to the third," "two to the third power," or "two raised to the third power."
If a number is raised to the second power, like 5^{2}, you can also say that the number is squared, such as "five squared."
If a number is raised to the third power, like 10^{3}, you can also say it is cubed, such as "ten cubed."
If a number has no exponent shown, like a simple 4, it is technically to the first power and can be rewritten as 4^{1}.
If the exponent is 0, and a "non-zero number" is raised to the "zero power", then the whole thing equals 1, such as 4^{0}=1 or even something like (3/8)^{0}=1