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Pavlova-9 [17]
3 years ago
8

Are regular polygons always the same?

Mathematics
2 answers:
rosijanka [135]3 years ago
8 0
A regular has to be the same on all sides BUT since it's regular the answer is yes... I think...
Pachacha [2.7K]3 years ago
4 0
No there's many of them is like the figures there are regular hexagon and irregular hexagon. and the other figures are the same

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What is 1 1/4 + 3 5/8 = when its reduced to lowest term.
nikdorinn [45]

Answer:

4 7/8 or 4.875

Step-by-step explanation:

1 1/4 + 3 5/8 = 4 7/8 or 4.875

PLEASE MARK ME AS BRAINLIEST UWU

5 0
3 years ago
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Which of the following shows a group of possible angles a triangle could have?
maw [93]

Answer:

<u><em>D) 50, 60, 70</em></u>

Step-by-step explanation:

The reason why it's D since a regular triangle equals up to 180 degrees in total and D is the only one that equals 180.

50+60+70= 180 degrees

<u><em>Hope this helps</em></u>

8 0
3 years ago
Let angle 1 and angle 2 be complementary. If má 1 = 4x +3 and m42 = x + 2, find the measure
Andre45 [30]

Answer:

m∠1 = 71°

Step-by-step explanation:

Angle 1 and 2 are complementary, meaning the measures of the two angles add up to 90°.

Set the measures of the two angles equal to 90°

(4x+3)+(x+2)=90\\

Combine like terms

5x+5=90

Solve for x

x=17

Plug the value of 'x' back into the given equation for the measure of angle 1

m

m∠1 = 71°

6 0
4 years ago
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Find the product of 30−−√ and 610−−√. Express it in standard form (i.E., ab√).
Zina [86]

we are given

\sqrt{30} *\sqrt{610}

we can radical formula

\sqrt{a} *\sqrt{b}=\sqrt{a*b}

we get

\sqrt{30} *\sqrt{610}=\sqrt{30*610}

\sqrt{30} *\sqrt{610}=\sqrt{3*61*100}

we can  also write as

\sqrt{30} *\sqrt{610}=\sqrt{100}*\sqrt{3*61}

\sqrt{30} *\sqrt{610}=10\sqrt{183}............Answer


7 0
3 years ago
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Find side x, giving your answer to 1 decimal place. 81 7 cm 40° X​
worty [1.4K]

Answer:

10.756 esa seria la respuesta

Step-by-step explanation:

6 0
2 years ago
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