Find four consecutive odd integers whose sum is 56

1 answer:

5 0

$2n+1;\ 2n+3;\ 2n+5;\ 2n+7-four\ consecutive\ odd\ integers\\\\(2n+1)+(2n+3)+(2n+5)+(2n+7)=56\\8n+16=56\\8n=56-16\\8n=40\\n=40:8\\n=5\\\\2n+1=2(5)+1=10+1=11\\\\Answer:\boxed{11;\ 13;\ 15;\ 17}$

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Answer:

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Step-by-step explanation:

1) Tyler has painted 5/7 of the 7/7 of the fence. So the total amount of the fence is (7/7)/(5/7) = 7/5 as much as what was already painted.

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