Question

Find four consecutive odd integers whose sum is 56

Answer 1

$2n+1;\ 2n+3;\ 2n+5;\ 2n+7-four\ consecutive\ odd\ integers\\\\(2n+1)+(2n+3)+(2n+5)+(2n+7)=56\\8n+16=56\\8n=56-16\\8n=40\\n=40:8\\n=5\\\\2n+1=2(5)+1=10+1=11\\\\Answer:\boxed{11;\ 13;\ 15;\ 17}$