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Roman55 [17]
3 years ago
8

1. Delia brushes her teeth 1/6 hour each day.

Mathematics
1 answer:
Travka [436]3 years ago
8 0
Part b = part 1 plus 7
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Taking finals pls help
Shtirlitz [24]

Answer:

It should be B $250 - - - - -

3 0
3 years ago
Guys please help me
Evgesh-ka [11]

Answer:

-2

Step-by-step explanation:

5 0
4 years ago
Fathers age is twice his daughter age but 16 years ago fathers age was 4 times his daughters age . Calculate their ages
zvonat [6]

Answer:

Father's age = 48

Daughter's age = 24

Step-by-step explanation:

Let x be father's age and y be daughter's age.

1st equation:

x = 2y

2nd equation:

(x - 16) = 4(y - 16)

Replacing value of x from 1st equation,

(2y - 16) = 4(y - 16)

2y - 16 = 4y - 64

4y - 2y = 64 - 16

2y = 48

y = 48/2

y = 24

And,

x = 2y

x = 2 x 24

x = 48

8x - x = 64 - 16

7x = 48

4 0
3 years ago
All of the following are equivalent, except _____.
marusya05 [52]

1. Given (12+3)x, we can sum the numbers in the parenthesis to get 15x

2. Given 12x+3x, we can factor x to get (12+3)x and get the same as 1.

3. Given (12+3x)x, we have to distribute the x and we have 12x+3x^2

4. This expression is already simplified.

7 0
3 years ago
Read 2 more answers
A twelve-sided die with sides labeled through will be rolled once. Each number is equally likely to be rolled. What is the proba
FromTheMoon [43]

<em>Complete Question:</em>

<em>A twelve-sided die with sides labeled 1 through 12 will be rolled once. Each number is equally likely to be rolled, what is the probability of rolling a number greater than 10?</em>

Answer:

P(T) = \frac{1}{6}

Step-by-step explanation:

Given

Number of Sides = 12

Required

Probability of obtaining a side greater than 10

We start by listing out the sample space;

S = \{1,2,3,4,5,6,7,8,9,10,11,12\}

n(S) = 12

Next, we list out digits greater than 10; Represent this with T

T = \{11,12\}

n(T) = 2

Probability of T is calculated as follows;

P(T) = \frac{n(T)}{n(S)}

P(T) = \frac{2}{12}

Divide the numerator and denominator by 2

P(T) = \frac{1}{6}

<em>Hence, the required probability is </em>\frac{1}{6}<em />

8 0
3 years ago
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