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pentagon [3]
3 years ago
5

Which is a counterexample that disproves the conjecture? After completing several multiplication problems, a student concludes t

hat the product of two binomials is always a trinomial.
Mathematics
1 answer:
Dahasolnce [82]3 years ago
5 0
When you make the product of a binomial of the kind x + a times other binomial that is of the kind x - a, you obtain another binomial (not a trinomial), so any example with that form will be a counterexample that disproves the conjecture:

(x + a) * (x - a) = x^2 - a^2

For example, (x +3) * (x - 3) = x^2 - 9. So, not always the product of two binomials is a trinomial.
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Please Help! Thanks!
svetlana [45]

Answer:

C, 20 units

Step-by-step explanation:

We see that both angles QRS and QTR are 90 degrees. In addition, angles SQR and RQT are equivalent (because they're both angle Q).

By AA Similarity, we know that triangle QTR is similar to triangle QRS.

With this similarity in mind, we can look at the ratios of corresponding lengths to set up a proportion. QR from triangle QTR is the hypotenuse, and it corresponds to hypotenuse QS from triangle QRS. So, we can write the ratio x/(9 + 16) = x/25.

Now, we see that long leg QT of triangle QTR corresponds to long leg QR of triangle QRS. So, another ratio we can write is: 16/x.

Finally, we set these two ratios equal to each other:

\frac{x}{25} =\frac{16}{x}

Cross-multiplying, we get: x^{2} =16*25=400.

Thus, x = \sqrt{400} =20. The answer is C, 20 units.

Hope this helps!

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