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4 years ago

Which of the following circles have their centers in the second quadrant? Check all that apply.

1 answer:

ivann1987 [24]4 years ago

7 0

The given circles are given in standard form:
(x - xc)² + (y - yc)² = r²

The second quadrant is the one that has negative x coordinates and positive y coordinates.

This said, let's see all your options:
A) (x - 5)² + (y - 6)² = 25
xc = -(-5) = +5
yc = -(-6) = +6
C (5 , 6) is in the first quadrant.

B) (x + 1)² + (y - 7)² = 16
xc = -(+1) = -1
yc = -(-7) = +7
C (-1 , 7) is in the second quadrant.

C) (x - 4)² + (y + 3)² = 32
xc = -(-4) = +4
yc = -(+3) = -3
C (4, -3) is in the fourth quadrant.

<span> D) (x + 2)² + (y - 5)²= 9</span>
xc = -(+2) = -2
yc = -(-5) = +5
C (-2 , +5) is in the second quadrant.

Therefore, the correct answers are B and D.

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The work of a student to solve the equation 3(2x − 4) = 8 + 2x + 6 is shown below:

Alexeev081 [22]

Answer:

The student made the error at step 2.

Step-by-step explanation:

The correct step will be:

Step 2; 6x − 12 = 14 + 2x

As 3 will be multiplied with 2x and 4 which will give 6x − 12

5 0

3 years ago

Could 8.8 cm, 8.0 cm and 8.8 cm be the side lengths of a triangle?

Alinara [238K]

Answer:

yes it is possible to have a triangle with 8.8 cm, 8.0 cm and 8.8 cm.

Step-by-step explanation:

Condition on sides of triangle:

The triangle inequality states that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side.
It is not possible to have sum to be less than the length of the third side.
A triangle with three given positive side lengths exists if and only if those side lengths satisfy the given condition
Let a, b and c be three sides of triangle.

$a + b > c\\a+c>b\\b+c>a$

Here, we are given that a = 8.8 cm, b = 8.0 cm, c = 8.8 cm

We check for the triangular inequality:

$1.~8.8 + 8.0 > 8.8\\16.8>8.8\\2.~8.8+8.8>8.0\\17.6>8.0\\3.~8.0+8.8>8.8\\16.8>8.8$

Thus, yes it is possible to have a triangle with given measurements.

7 0

3 years ago

John took all his money from his savings account. He spent $110 on a radio and 4/11 of what was left on presents for his friend

svp [43]

Answer:

$1210

Step-by-step explanation:

Let x be total amount

First John spent $110 on a radio and 4/11 of what was left on presents for his friends so he was left with

$\frac{7}{11}(x-110)=\frac{7}{11}x-70$

Then he put 2/5 of his remaining money into a checking account

$\frac{3}{5}\left(\frac{7}{11}x-70\right)$

Rest he donated to charity

$420=\frac{3}{5}\left(\frac{7}{11}x-70\right)\\\Rightarrow \left(\frac{7}{11}x-70\right)=\frac{2100}{3}\\\Rightarrow \frac{7}{11}x-70=700\\\Rightarrow \frac{7}{11}x=770\\\Rightarrow x=1210$

Hence total amount of money John originally had was $1210

8 0

3 years ago

A roll of film for this camera costs $4.79. There

frutty [35]

Answer:

The total cost is $16.96

The cost per photo is $1.06

Step-by-step explanation:

Hello!

1 roll of film costs $4.79. 1 roll of film has 16 photos. To develop the 16 photos, you need to pay $12.17.

First, let's find the total cost for the film and the development for 1 roll of film:

Total Cost = Cost of Film + Cost of developing
Total Cost = $4.79 + $12.17
Total Cost = $16.96

<u>The total cost of 16 photos is $16.96</u>

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Now, we have to find the price per picture on the roll of film. We know that there are 16 shots on the film, so we can simply divide the total price by 16 to find the price per picture.

Divide:

$16.96 ÷ 16
($16 ÷ 16) + ($0.96 ÷ 16)
$1 + $0.06
$1.06

<u>The price per photo is $1.06</u>

8 0

2 years ago

Ay-by=c <br> solve for "y"

True [87]

$\sf Ay-by = c\\\\ Factor~out~y\\ y(A-b) = c\\\\ Divide A-b~on~both~sides\\y = \frac{c}{A-b}$

4 0

3 years ago