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valkas [14]
3 years ago
10

Which of the following circles have their centers in the second quadrant? Check all that apply.

Mathematics
1 answer:
ivann1987 [24]3 years ago
7 0
The given circles are given in standard form:
(x - xc)² + (y - yc)² = r²

The second quadrant is the one that has negative x coordinates and positive y coordinates.

This said, let's see all your options:
A) (x - 5)² + (y - 6)² = 25
xc = -(-5) = +5
yc = -(-6) = +6
C (5 , 6) is in the first quadrant.

B) (x + 1)² + (y - 7)² = 16
xc = -(+1) = -1
yc = -(-7) = +7
C (-1 , 7) is in the second quadrant.

C) (x - 4)² + (y + 3)² = 32
xc = -(-4) = +4
yc = -(+3) = -3
C (4, -3) is in the fourth quadrant.

<span> D) (x + 2)² + (y - 5)²= 9</span>
xc = -(+2) = -2
yc = -(-5) = +5
C (-2 , +5) is in the second quadrant.

Therefore, the correct answers are B and D.
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3 years ago
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Evaluate the expression when a= 4, b= - 2, and c= 7 - -&gt; 5a - 9 (b - c)
ollegr [7]

Answer:

65

Step-by-step explanation:

Given the following question:

5a-9(b-c)
a = 4
b = 2
c = 7

In order to find the answer, we need to substitute the variables with the numbers given, and then solve using PEMDAS.

5\times4-9\times(2-7)
2-7=-5
5\times4-9\times-5
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9\times-5=-45
20--45
20+45=65
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Hope this helps.

8 0
2 years ago
PLEASE SHOW YOUR WORK WITH YOUR ANSWER. Two bags had 50 kilograms of sugar each. After taking out 3 times as much sugar from bag
Svetllana [295]

Answer:

Bag 1: 20

Bag 2: 40

Step-by-step explanation:

Let x be the amount taken out of bag 2

Then the amount left in each bag can be written as:

Bag 1: 50-3x

Bag 2: 50-x

Since we know that half of bag 2 is bag 1, that gives us:

50-3x = 1/2(50-x)

-> 50-3x = 25-x/2

Now lets isolate x and solve:

25 = 5x/2

-> 50 = 5x

-> x = 10

So plug x bag in for the original equations:

Bag 1: 50-3x = 50-3(10) = 20

Bag 2: 50-x = 50-10 = 40

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