Answer:
point 1 (0,-6)
point 2(2,0)
Step-by-step explanation:
Dy/dx = y/(x^2)
dy/y = dx/(x^2)
int[dy/y] = int[dx/(x^2)] ... apply integral to both sides
ln(|y|) = (-1/x) + C
|y| = e^{(-1/x) + C}
|y| = e^C*e^(-1/x)
|y| = C*e^(-1/x)
y = C*e^(-1/x)
So you have the correct answer. Nice job.
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Check:
y = C*e^(-1/x)
dy/dx = d/dx[C*e^(-1/x)]
dy/dx = d/dx[-1/x]*C*e^(-1/x)
dy/dx = (1/(x^2))*C*e^(-1/x)
is the expression for the left hand side (LHS)
y/(x^2) = [C*e^(-1/x)]/(x^2)
y/(x^2) = (1/(x^2))*C*e^(-1/x)
is the expression for the right hand side (RHS)
Since LHS = RHS, this confirms the solution for dy/dx = y/(x^2)
For this case we have the following data:
The original dimensions of the drawing are:
If the copier zoom is at 120%, we can find the new dimensions of the drawing by making a rule of three:
Width:
3 ----------> 100%
x ----------> 120%
Where x represents the new width of the drawing:

Long:
5 ----------> 100%
y ----------> 120%
Where y represents the new long of the drawing:

Thus, the new dimensions are 3.6 cm wide and 6 cm long
Answer:
the longer dimension of the new drawing is 6cm
Sasha is incorrect. you would add the 8x and the 3x not subtract them. Dante is correct because he adds 3x and 5x and he also adds 6 to both sides of the equation. Hope I helped!