Question

2 times the square root of 27 minus the square root of 48

Answer 1

$2 \sqrt{27}- \sqrt{48}=2 \sqrt{9*3}- \sqrt{16*3} =2*3 \sqrt{3}- 4 \sqrt{3}=6 \sqrt{3}-4 \sqrt{3} = \\ =2 \sqrt{3}$