The answer will be x^3-5. Hope it help!
Answer:
WTH is that bro, If I had to answer this between a life or death situation I'd die
Y = t*e^(-t/2)
y' = t' [e^(-t/2)] + t [e^(-t/2)]' = e^(-t/2) + t[e^(-t/2)][-1/2]=
y' = [e^(-t/2)] [1 - t/2] = (1/2)[e^(-t/2)] [2 - t] = - (1/2) [e^-t/2)] [t -2]
identity used is
x³ + y³+ z³– 3xyz = (x + y + z) (x² + y² + z² – xy – yz – zx).
then use
(x+y+z)² = x²+y²+z²+2(xy+yz+xz)
225= 83 + 2(xy+yz+xz)
xy+yz+xz = (225-83)/2
xy+yz+xz= 142/2
xy+yz+xz= 71
ok
now use identity
x³ + y³+ z³– 3xyz = (x + y + z) (x² + y² + z² – xy – yz – zx).
now
x³ + y³+ z³– 3xyz = 15 (83 – xy – yz – zx).
= 15[83 - (71)]
= 15×12
=180
Pythagorean Theorem: A^2 + B^2 = C^2
<span>We know A and C, let's find B by doing it backwards </span>
<span>C^2 - A^2 = B^2 </span>
<span>4^2 - 7 (square root of 7 squared is just 7) = B^2 </span>
<span>16 - 7 = B^2 </span>
<span>9 = B^2 </span>
