Mrs. Bowser spends $39 on 3 slices of pizza and 5 bags of popcorn. Mrs. Lassetter spends $36.50 on 5 slices of pizza and 2 bags
1 answer:
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Answer:
Regression Line is given by,
y = 22.909 + 0.209 x
The course grade of a student in the course who spent an average of 103 minutes in the course each week is: 22.909 + 0.209 × 103 = 44.436
Step-by-step explanation:
The equation of Regression equation is of the form of:
y = a + bx
where, a is intercept and b is slope
The formula for a and b is given by,
Here, ∑X = 1149.8, ∑Y = 377.2, ∑XY = 93115.95, ∑X² = 320246.72
Thus, a = 22.909
and b = 0.209
Thus, Regression Line is given by,
y = 22.909 + 0.209 x
Thus, The course grade of a student in the course who spent an average of 103 minutes in the course each week is: 22.909 + 0.209 × 103 = 44.436
Now plotting these line:
Answer:
2598 square kilometers
Step-by-step explanation:
Hello
Step 1
year one
using a rule of three is possible to find how much is 8.75 od 4500 km2
Let
if
4500 km2 ⇒ 100$
x?km2 ⇒8.75
do the relation and isolate x
at the end of the year one, the area will be
4500-393.75=4106.25
this will be the initial area for the year 2.
Step 2
repite the step 1 with area initial =4106.25 km2
4106.25 km2 ⇒ 100$
x?km2 ⇒8.75
do the relation and isolate x
at the end of the year 2, the area will be
4106-359.29=3746.70
this will be the initial area for the year 3.
Step 3
repite the step 1 with area initial =4106.25 km2
3746.70 km2 ⇒ 100$
x?km2 ⇒8.75
do the relation and isolate x
at the end of the year 3, the area will be
3746.70-327.83=3419.09
this will be the initial area for the year 4.
Step 4
year four
repite the step 1 with area initial =3419.09 km2
3419.09 km2 ⇒ 100$
x?km2 ⇒8.75
do the relation and isolate x
at the end of the year 4, the area will be
3419.09-299.173=3119.82
this will be the initial area for the year 5.
Step 5
year five
repite the step 1 with area initial =3119.82 km2
3119.82 km2 ⇒ 100$
x?km2 ⇒8.75
do the relation and isolate x
at the end of the year 5, the area will be
3119.82-272.99=2846.92
this will be the initial area for the year 6.
Step 6
year six
repite the step 1 with area initial =2846.92km2
2846.92 km2 ⇒ 100$
x?km2 ⇒8.75
do the relation and isolate x
at the end of the year six, the area will be
2846.92-249.10=2597.82 square kilometers
Have a great day.