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Nataly [62]
3 years ago
10

What percentage of goldfish will have lengths between 4.6 inches and 9.4 inches? 34%

Mathematics
2 answers:
maxonik [38]3 years ago
8 0

Answer:

95%

Step-by-step explanation:

ella [17]3 years ago
7 0

Answer:

95%

Step-by-step explanation:

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Please help!
n200080 [17]

Answer:

32.5

Step-by-step explanation:

7h+1.50d

step 2: plug in the hours he worked and the amount of deliveries made.

(7x4)+(1.50x3)=32.5

3 0
2 years ago
Part 2 of Question please help me <br> and thank you for your help
san4es73 [151]

1 tick represents 8 units

4 0
2 years ago
"The manager for State Bank and Trust has recently examined the credit card account balances for the customers of her bank and f
yuradex [85]

Answer:

a

   P(X = 4 ) = 0.1876

b

   P(X \le 4)  =  0.8358

Step-by-step explanation:

From the question we are told that

The proportion that has outstanding balance is p = 0.20

The sample size is n = 15

Given that the properties of the binomial distribution apply, for a randomly selected number(X) of credit card

X \  \ ~ Bin (n , p )

Generally the probability of finding 4 customers in a sample of 15 who have "maxed out" their credit cards is mathematically represented as

P(X = 4 ) =  ^nC_4 * p^4 * (1 - p)^{n-4}

=> P(X = 4 ) =  ^{15}C_4 * (0.20)^4 * (1 - 0.20)^{15-4}

Here C stand for combination

=> P(X = 4 ) = 0.1876

Generally the probability that 4 or fewer customers in the sample will have balances at the limit of the credit card is mathematically represented as

P(X \le 4) =  [ ^{15}C_0 * (0.20)^0 * (1 - 0.20)^{15-0}]+[ ^{15}C_1 * (0.20)^1 * (1 - 0.20)^{15-1}]+\cdots+[ ^{15}C_4 * (0.20)^4 * (1 - 0.20)^{15-4}]

=>   P(X \le 4)  =  0.8358

4 0
3 years ago
Bacteria colonies increase by 37% every 2 days. If you start with 55 microorganisms, how large would the colony be after 10 days
ahrayia [7]

The number of microorganisms that I will have after 10 days would be: 245.41 microoganisms.

<h3>How to calculate the number of microorganisms that I will have after 10 days?</h3>

To calculate the number of microorganisms that I will have after 10 days, I must perform the following operations:

We need to find 37% of 55 as shown below:

  • 55 ÷ 100 = 0.55
  • 0.55 x 37% = 20.35
  • 55 + 20.35 = 75.35

So after 2 days I will have 75.35 microorganisms.

  • 75.35 ÷ 100 = 0.75
  • 0.7535 x 37% = 27.87
  • 75.35 + 27.87 = 103.22

On the fourth day I will have: 103.22 microorganisms.

  • 103.22 ÷ 100 = 1.0322
  • 1.0322 x 37% = 38.19
  • 103.22 + 38.19 = 141.41

On the sixth day I will have 141.41 microorganisms.

  • 141.41 ÷ 100 = 1.4141
  • 1.4141 x 37% = 52.32
  • 141.41 + 52.32 = 193,73

On the eighth day I will have 193.73 microorganisms.

  • 193.73 ÷ 100 = 1.9373
  • 1.9373 x 37% = 71.68
  • 193.73 + 71.68 = 265.41

On the tenth day I will have 245.41 microoganisms.

Learn more about percentages in: brainly.com/question/13450942

#SPJ1

3 0
1 year ago
A bottle contains 1.7 L of water. A second bottle contains 450 mL of water. What is the total number of mL of water in both bott
amm1812

Answer:

2150 mL

Step-by-step explanation:

1L=1000mL - convert

1.7mL=1700mL - convert problem numbers

1700+450mL - addition

2150mL- answer

5 0
2 years ago
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