7.
(2b^2+7b^2+b)+(2b^2-4b-12)
(9b^2+b)+(2b^2-4b-12)
9b^2+b+2b^2-4b-12
11b^2+b-4b-12
11b^2-3b-12
8.
(7g^3+4g-1)+(2g^2-6g+2)
7g^3+4g-1+2g^2-6g+2
7g^3-2g-1+2g^2+2
7g^3-2g+1+2g^2
7g^3+2g^2-2g+1
Hope this helps!
According to a calculator, this is the answer: 0.1923076923. Hope this helped?
It would take 2.25 minutes to complete 3 laps because each lap takes .75 minutes.
<h3>
Answer: 270.58 dollars</h3>
======================================================
Work Shown:
- A = account value after t years
- P = principal or amount deposited = 800
- r = interest rate in decimal form = 0.06
- n = number of times we compound per year = 1
- t = number of years = 5
So,
A = P*(1+r/n)^(n*t)
A = 800*(1+0.06/1)^(1*5)
A = 1070.58046208
A = 1070.58
After five years, the account will have $1,070.58 in it.
The amount of interest earned is A-P = 1070.58 - 800 = 270.58 dollars.
Answer:
0.5
Step-by-step explanation:
The given ordered pairs are: (1,2) (2,2.5) (3,3) (4,3.5) (5,4)
The corresponding sequence is :
2,2.5,3,3.5, 4,....
We can see that there is a common difference of d=0.5.
Better still we could use the slope formula:
We substitute the point (1,2) and (2,2.5).
The rate of change of this sequence is:
