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ad-work [718]
3 years ago
5

There’s only one granola bar left out of the pan of 10 bars if Will and Rachel decide to split the last granola bar what fractio

n of the entire pan of granola bars will beachfront receive
Computers and Technology
1 answer:
maks197457 [2]3 years ago
8 0
Do not know about the beachfront
the last bar is 1/10    half of that is 1/10  x 1/2   which equals   1/20
You might be interested in
time to throw poggers xqc time to throw pogchamp time to throw pogchamp time to throw pogchamp time to throw pogchamp time to th
Effectus [21]
Yes thank you very much
6 0
3 years ago
Read 2 more answers
Write a program that asks for the number of calories and fat grams in a food. The program should display the percentage of calor
Zigmanuir [339]

Answer:

 The solution code is written in Python 3:

  1. calories = int(input("Enter number of calories: "))
  2. fats = int(input("Enter number of fat in grams: "))
  3. if(calories > 0 and fats > 0):
  4.    cf = fats * 9
  5.    if(cf < calories):
  6.        percent = cf / calories  
  7.        if(percent < 0.3):
  8.            print("Food is low in fat")
  9.    else:
  10.        print("Error input. Calories from fat cannot more than total calories")
  11. else:
  12.    print("Error input. Calories and fats must be more than 0")

Explanation:

Firstly, use input function to ask user to enter total number of calories and fat in grams (Line 1-2)

Next we do the first input validation to check if the calories and fats are more than 0 (Line 4). If so apply formula to calculate calories from fats. If not, print error input message (Line 5, 13)

Then we proceed to next input validation to check if calories from fact more than total calories. If so, proceed to calculate percentage of calories from fats and if it is lower than 30%, display the appropriate message (Line 6 - 9). If fail the second input validation, the program will display another error input message again (Line 11)

7 0
4 years ago
Perform algorithm time measurement for all three quadratic sorting algorithms for Best Case (already sorted), Average Case (rand
Kaylis [27]

Answer:

Experiment size : 50,000

==================================

Selection sort :

---------------------------------------------------------

Worst case : 0.162

Average case : 0.116

Best case : 0.080

Insertion sort :

---------------------------------------------------------

Worst case : 0.162

Average case : 0.116

Best case : 0.080

Bubble sort:

--------------------------------------------------------

Worst case : 0.211

Average case : 0.154

Best case : 0.117

Experiment size : 100,000

==================================

Selection sort :

---------------------------------------------------------

Worst case : 0.316

Average case : 0.317

Best case : 0.316

Insertion sort :

---------------------------------------------------------

Worst case : 0.316

Average case : 0.317

Best case : 0.316

Bubble sort:

--------------------------------------------------------

Worst case : 0.482

Average case: 0.487

Best case : 0.480.

Experiment size : 200,000

==================================

Selection sort :

---------------------------------------------------------

Worst case : 1.254

Average case : 1.246

Best case : 1.259

Insertion sort :

---------------------------------------------------------

Worst case : 1.254

Average case : 1.246

Best case : 1.259

Bubble sort:

--------------------------------------------------------

Worst case : 1.990

Average case : 2.009.

Best case : 1.950

Explanation:

[NB: since it is very long there is the need for me to put it it a document form. Kindly check the doc. Files. The file A is the sort Analysis.Java file and the file B is the sort.Java file].

The concept of algorithm time measurement strictly depends on the following;

=> The measurement of time, space or energy on different sizes.

=> Plotting of the measurements and characterizing them.

=> Running or implementation of the algorithm.

Programming language such as Java can be used in accessing the operating system clock and Java had two static methods.

KINDLY CHECK BELOW FOR THE ATTACHMENT.

Download doc
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark"> doc </span>
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark"> doc </span>
5 0
3 years ago
Develop a program to sort a file consisting of bonks details in the alphabetical order of author names. The details of books inc
olga2289 [7]

Use the knowledge in computational language in C++ to write the a code with alphabetical order of author name.

<h3>How to define an array in C++?</h3>

An Array is a set of values ​​arranged in lists and accessible through a positive numeric index. So, we have that each position of our Array is a variable of the type of our Array, so we have to have a way to initialize this set of variables.

<em>#include <iostream></em>

<em>#include <iomanip></em>

<em>#include <fstream></em>

<em>#include <string></em>

<em>using namespace std;</em>

<em>struct Book {</em>

<em>    string title;</em>

<em>    string author;</em>

<em>};</em>

<em>const int ARRAY_SIZE = 1000;</em>

<em>Book books [ARRAY_SIZE];</em>

<em>string pathname;</em>

<em>ifstream library;</em>

<em>int LoadData();</em>

<em>void ShowAll(int count);</em>

<em>void ShowBooksByAuthor(int count, string name);</em>

<em>void ShowBooksByTitle(int count, string title);</em>

<em>void sortByTitle(int count, string title);</em>

<em>void sortByAuthor(int count, string author);</em>

<em>int main()</em>

<em>{   </em>

<em>    int count = 0;</em>

<em>    char selector = 'q', yesNoAnswer = 'n';</em>

<em>    string name;</em>

<em>    string title;</em>

<em>      cout << "Welcome to Forrest's Library Database." << endl;</em>

<em>    cout << "Please enter the name of the backup file: ";</em>

<em>    getline(cin, pathname);</em>

<em>    LoadData();</em>

<em>    count = LoadData();</em>

<em>    cout  << count << " records loaded successfully." << endl;</em>

<em>    do </em>

<em>    {</em>

<em>        cout << endl << "\t(S)how All, Search (A)uthor, Search (T)itle, (Q)uit: "; </em>

<em>        cin >> selector;</em>

<em>        selector = toupper(selector);</em>

<em>        switch(selector)</em>

<em>        {</em>

<em>            case 'S': </em>

<em>                sortByTitle(count, title);</em>

<em>                if (count <= 0)</em>

<em>                    cout << "No counts found!\n";</em>

<em>                else</em>

<em>                    ShowAll(count);</em>

<em>                break;</em>

<em>            case 'A': </em>

<em>                sortByAuthor(count, name);</em>

<em>                cout << "bookAuthor: ";</em>

<em>                cin.ignore();</em>

<em>                getline(cin, name);</em>

<em>                if (count <= 0)</em>

<em>                    cout << "No records found!\n";</em>

<em>                else</em>

<em>                    ShowBooksByAuthor(count, name); </em>

<em>                break;</em>

<em>            case 'T': </em>

<em>                sortByTitle(count, title);</em>

<em>                cout << "bookTitle: ";</em>

<em>                cin.ignore();</em>

<em>                getline(cin, title);</em>

<em>                if (count <= 0)</em>

<em>                    cout << "No records found!\n";</em>

<em>                else</em>

<em>                    ShowBooksByTitle(count, title);      </em>

<em>                break; </em>

<em>        }</em>

<em>    }</em>

<em>    while (selector != 'q' && selector != 'Q'); </em>

<em>    return 0;</em>

<em>}</em>

<em>int LoadData() </em>

<em>{</em>

<em>    int count = 0;</em>

<em>    int i = 0;</em>

<em>    library.open(pathname);</em>

<em>    ifstream library(pathname);</em>

<em>    if (!library)</em>

<em>    {</em>

<em>        cout << "Cannot open backup file" << endl;</em>

<em>        return 0;</em>

<em>    }</em>

<em>    while (!library.eof())</em>

<em>    {</em>

<em>        getline(library, books[count].title);</em>

<em>        getline(library, books[count].author);</em>

<em>        count++;</em>

<em>    }</em>

<em>    return count;</em>

<em>}</em>

<em>void ShowAll(int count) </em>

<em>{</em>

<em>    for (int i = 0; i < count; i++)</em>

<em>    {</em>

<em>       cout << books[i].title << " " << "(" << books[i].author << ")" << endl;</em>

<em>    }</em>

<em>}</em>

<em>void ShowBooksByAuthor(int count, string name) </em>

<em>{</em>

<em>    int j = 0;</em>

<em>    for (int i = 0; i < count; i++)</em>

<em>    {</em>

<em>        if(books[i].author.find(name) < 100) </em>

<em>        {</em>

<em>            cout << books[i].title << " " << "(" << books[i].author << ")" << endl;</em>

<em>            j++;</em>

<em>        }</em>

<em>    }</em>

<em>    cout << j << " records found";}</em>

<em>void ShowBooksByTitle(int count, string title) </em>

<em>{</em>

<em>    int j = 0;</em>

<em>    for (int i = 0; i < count; i++)</em>

<em>    {</em>

<em>        if(books[i].title.find(title) < 100)</em>

<em>        {</em>

<em>            cout << books[i].title << " " << "(" << books[i].author << ")" << endl;</em>

<em>            j++;</em>

<em>        }</em>

<em>    }</em>

<em>    cout << j << " records found";</em>

<em>}</em>

<em>void sortByTitle(int count, string title) {</em>

<em>    string temp;</em>

<em>    for (int i = 0; i < count; i++) {</em>

<em>        for(int j = 0; j < count - i; j++) {</em>

<em>            if (books[j].title > books[j + 1].title) {</em>

<em>                temp = books[j].title;</em>

<em>                books[j].title = books[j + 1].title;</em>

<em>                books[j + 1].title = temp;</em>

<em>            }</em>

<em>        }</em>

<em>    }</em>

<em>}</em>

<em>void sortByAuthor(int count, string name) {</em>

<em>    string temp;</em>

<em>    for (int i = 0; i < count; i++) {</em>

<em>        for(int j = 0; j < count - i; j++) {</em>

<em>            if (books[j].author > books[j + 1].author) {</em>

<em>                temp = books[j].author;</em>

<em>                books[j].author = books[j + 1].author;</em>

<em>                books[j + 1].author = temp;</em>

<em>            }</em>

<em>        }</em>

<em>    }</em>

<em>}</em>

See more about C++ at brainly.com/question/19705654

6 0
2 years ago
Write the definition of a function typing_speed, that receives two parameters. The first is the number of words that a person ha
Lera25 [3.4K]

Answer:

The definition of function is as follows:

def typing_speed(number_of_words,Time_Interval):

number_of_words>=0  

Time_Interval>0

speed=float(60*number_of_words/Time_Interval)

return speed

Explanation:

Above function is defined step-by-step as follows:

        def typing_speed(number_of_words,Time_Interval):

  • A function named typing speed has two arguments, num_of_words and Time_Interval.

                             number_of_words>=0  

                             Time_Interval>0

  • The variable number_of_words is the number of words entered that a person enters, they must be greater than or equal to 0. Where as Time_Interval is the variable for counting the time span in seconds, it must be greater than 0.

                    speed=float(60*number_of_words/Time_Interval)

                    return speed

  • For determining result firstly the seconds are converted int minutes by multiplying with 60 and number_of_words is divided with Time_Interval in order to get words per minute. The return value will give speed which has data type float.

4 0
3 years ago
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