Answer:
Transport Layer
Explanation:
The transport layer which is responsible for end-to-end communication over a network. Transport Layer breaks the data, allocated by Application layer in smaller units called segments. It is used to number every byte in the segment. It is also responsible for error correction and provides reliability to the user. It allows the host to send and receive error corrected data, messages or packets over a network and ensures that data should be received in the same sequence in which it was sent. It also enables multiplexing and flow control.
Click the font drop-down box in the tool settings bar. Select "Arial." 6. Press "Alt-3" using your keyboard number pad's "3" key to insert the heart symbol<span>.</span>
Answer: Robert H. Goddard
Explanation: he developed and flew the first liquid-propellant rocket
Answer:
C. Trojan
Explanation:
In Cybersecurity, vulnerability can be defined as any weakness, flaw or defect found in a software application or network and are exploitable by an attacker or hacker to gain an unauthorized access or privileges to sensitive data in a computer system.
This ultimately implies that, vulnerability in a network avail attackers or any threat agent the opportunity to leverage on the flaws, errors, weaknesses or defects found in order to compromise the security of the network.
In this scenario, a security administrator is reviewing the following information from a file that was found on a compromised host: "cat suspiciousfile.txt."
Some of the ways to prevent vulnerability in a network are;
1. Ensure you use a very strong password with complexity through the use of alphanumerics.
2. You should use a two-way authentication service.
3. You should use encrypting software applications or services.
Answer and Explanation:
Given that total number of records in a file = 100000
Each record consists of= 240 bytes
Given that B= 2400 bytes.
Then total blocks in file = 100000 records * 240 / 2400
= 10000 blocks.
Time that will take for exhaustive read
= s + r + b.btt
= 16 + 8.3 + (10000) * 0.8
= 8024.3 msec
Now as per given X be the number of records that are searched randomly and it takes more than exhaustive read time.
Hence, X (s + r + btt) > 8024.3
X (16+8.3+0.8) > 8024.3
X > 8024.3/25.1
So that, X > 319.69
Hence, atleast 320 random reads should be made to search the file
