Answer:
V =113.04
Step-by-step explanation:
A sphere has a surface area of 113.04
SA = 4 pi r^2
113.04 = 4 pi r^2
Let pi 3.14
113.04 = 4 *(3.14) r^2
113.04 = 12.56 r^2
Divide each side by 12.56
113.04/12.56 = r^2
9 = r^2
Take the square root of each side
3 =r
We want to find the volume
V = 4/3 pi r^3
V = 4/3 (3.14) 3^3
V =113.04
Y=2/3x+4
Y intercept is 4
Points hit 2 up 3 over
The largest possible volume of the given box is; 96.28 ft³
<h3>How to maximize volume of a box?</h3>
Let b be the length and the width of the base (length and width are the same since the base is square).
Let h be the height of the box.
The surface area of the box is;
S = b² + 4bh
We are given S = 100 ft². Thus;
b² + 4bh = 100
h = (100 - b²)/4b
Volume of the box in terms of b will be;
V(b) = b²h = b² * (100 - b²)/4b
V(b) = 25b - b³/4
The volume is maximum when dV/db = 0. Thus;
dV/db = 25 - 3b²/4
25 - 3b²/4 = 0
√(100/3) = b
b = 5.77 ft
Thus;
h = (100 - (√(100/3)²)/4(5.77)
h = 2.8885 ft
Thus;
Largest volume = [√(100/3)]² * 2.8885
Largest Volume = 96.28 ft³
Read more about Maximizing Volume at; brainly.com/question/1869299
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Answer:
Angle A must be acute.
Explanation:
Both angle A and C must be acute. The sum of the angles in a triangle is 180°.
An obtuse angle is more than 90°, so the sum of the remaining 2 angles has to be less than 90°.
Note that it is impossible to have:
<span>2 right angles in a triangle, because <span>90°+90°=180</span>° and the third angle still needs to be added.1 obtuse and 1 right angle in a triangle, their sum is more than 180°2 obtuse angles in a triangle, their sum is more than 180°</span>
It is possible to have an obtuse-angled isosceles triangle, but the vertex angle must be obtuse and the equal base angles will be acute.
The answer is A. 3375 mm^3. This is because, since it is a cube, all of the sides are the same, meaning that you have to do 15 × 15 = 225, and then multiply that by 15 which is 3375. I hope this helps!
