Answer: 4/9
Step-by-step explanation:
The probability that annie picks a duck Pt= the probability of picking a duck without accounting for the added one (Po)+ probability of picking the added bird and it's a duck(Pi)
Pt = Po+Pi
Since the total number of birds in the right pond is 10 after the addition of one by john
Po= 4/10
Pi= the of john adding a duck × the probability of annie picking the added bird
Pi= 4/9 × 1/10
Pi = 4/90
Pt= 4/10 + 4/90
Pt = (36+4)/90
Pt=40/90
Pt= 4/9
(This implies that the probability of picking a duck remain the same even after the addition of one bird from the left ponds because they both have equal proportions of duck and geese i.e the initial number of duck and geese in both right and left ponds are 4 and 5 respectively)
Thanks.
The set given by the project grade is {1, 2, 3, 4, 5}. If the random variable, X, is the project grade, the mean of the probability distribution is determined by:
Sum = 1 + 2 + 3 + 4 +5
= 15
Mean of the probability distribution is 15/n, where n = 5
= 15/ 5
= 3
The simplest ratio is 1/3. Equivalent ratios would be 3/9 and 5/15.
Answer:
1. Range is 37,IQR is 16.5, MAD is 9
2.Range is 35,IQR is 14, MAD is 8
3. Range is 76,IQR is 37, MAD is 19.1
4. Range is 8, IQR is 4, Mad is 20.4
5. Range is 62,IQR is16 , MAD is 13.08
6. Range is 42,IQR is 23,MAD is 12
Step-by-step explanation:
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