That’s the same thing I’m on
There are two numbers whose sum is 64. The larger number subtracted from 4 times the smaller number gives 31. Then the numbers are 45 and 19
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Given that, There are two numbers whose sum is 64.
Let the number be a and b in which a is bigger.
Then, a + b = 64 ------ eqn (1)
The larger number subtracted from 4 times the smaller number gives 31.
4 x b – a = 31
4b – a = 31 ----- eqn (2)
We have to find the numbers.
So, from eqn (2)
a = 4b – 31
Subatitute a in (1)
4b – 31 + b = 64
On solving we get
5b = 64 + 31
5b = 95
b = 19
So, b = 19, then eqn 1
a + 19 = 64
On simplification,
a = 64 – 19
a = 45
Hence, the two numbers are 45 and 19
This is a normal distribution with a Mean: 14 g/dL and a Standard deviation: 1 g/dL.
A ) Hemoglobin levels less than 13:
13 = 14 - 1 = Mean - 1 SD
0.16 x 200 = 32
Answer: 32 people.
B ) Hemoglobin levels greater than 14 :
0.50 x 200 = 100
Answer: 100 people.
4.15, 6.3, 8.45, 10.6, 12.75
You just subtract 4.15 from 6.3 and you get a difference of 2.15. Then you add it to 8.45 giving you the answer of 10.6 and then you add 2.15 to that getting 12.75.
The product of two radicals is equal to the radicand. The square root deletes itself.
So the result is y^3
