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Thepotemich [5.8K]
3 years ago
7

Roman solved the equation 5a+2b=10 for a. His steps are shown below. 1. Subtract 2b: 5a+2b-2b=10-2b 2. Multiply by 5: 5a+10-2b W

hich statement about Roman’s work is true? In step 1, he needed to add 2b to both sides of the equation. In step 1, he needed to divide both sides of the equation by 2b. In step 2, he needed to divide both sides of the equation by 5. In step 2, he needed to subtract 5 from both sides of the equation.
Mathematics
2 answers:
natima [27]3 years ago
4 0

Answer:

C.) In step 2, he needed to divide both sides of the equation by 5

Step-by-step explanation:

YOUR WELCOME!! I took the test on Edge!! :)

VladimirAG [237]3 years ago
3 0

Answer:

In step 2, he needed to divide both sides of the equation by 5

Step-by-step explanation:

we have

5a+2b=10

Solve for a------> That means isolate the variable "a"

step 1

Subtract 2b to both sides

5a+2b-2b=10-2b

5a=10-2b

step 2

Divide by 5 both sides

5a/5=(10-2b)/5

a=(10-2b)/5

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cricket20 [7]

Answer:

C. The functions have the same y-intercept

Step-by-step explanation:

In slope intercept form, y = mx + b, b represents the y-intercept, and in the first function the y-intercept is 10.

The y-intercept is when x = 0, and in the chart, when x equals 0, y equals 10.

10 = 10, so they have the same y-intercept.

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3 years ago
f the principal is $350 and the interest rate is 3 percent, what is the simple interest earned in one year?
damaskus [11]

Answer:

$10.50

Step-by-step explanation:

The formula is Balance= Principle (starting amount) x Time x Interest rate. 350 x .03 x 1 is $10.50.

8 0
3 years ago
Find the perimeter of a triangle with vertices A(3, 1), B(2, -1), and C(-3, 2). Leave
natulia [17]

The perimeter of triangle is: 14.15 units

Step-by-step explanation:

First of all we have to find the lengths of sides of triangles

Given

A(3, 1), B(2, -1), and C(-3, 2)

The distance formula will be used to find the lengths of sides

d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\

So,

AB = \sqrt{(2-3)^2+(-1-1)^2}\\=\sqrt{(-1)^2+(2)^2}\\=\sqrt{1+4}\\=\sqrt{5}\\=2.24\ unitsBC = \sqrt{(-3-2)^2+(2+1)^2}\\=\sqrt{(-5)^2+(3)^2}\\=\sqrt{25+9}\\=\sqrt{34}\\= 5.83\ units\\AC = \sqrt{(-3-3)^2+(2-1)^2}\\=\sqrt{(-6)^2+(1)^2}\\=\sqrt{36+1}\\=\sqrt{37}\\=6.08\ units

The perimeter of triangle will be:

P = AB+BC+AC\\= 2.24+5.83+6.08\\=14.15\ units

Hence,

The perimeter of triangle is: 14.15 units

Keywords: Triangle Perimeter

Learn more about perimeter at:

  • brainly.com/question/573729
  • brainly.com/question/572693

#LearnwithBrainly

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aivan3 [116]

Answer:

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Step-by-step explanation:

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