To find the amplitude and period you need to be familiar with the following equation. Also you need to know that the standard cos has a period of

and the midline is a line that runs between the max and min of the y-values of the function.
Equations:f(x) = A cos(Bx +C) + D
f(x) = -4 cos(2x -n) + 3
A = amplitude = |-4| = 4
B = 2
C = phase shift = n = 0
D = vertical shift = midline = 3
Amplitude = 4
Find the period:
Find the midline:We know that the amplitude is 4 so we have a range from -4 to 4. The standard y = cos(x) has its midline at 0 so y = 0. This is also true for y = -4 cos(x). In your equation though, you have a vertical shift of +3 so this changes our midline. With an amplitude of 4, which gives us a range from -4 to 4(our y-values), the shift moves this up by 3 so that means we will have new
y-values and a range of -1 to 7. Now we need to find the midline(
the middle of our y-values) of our new range. We can find this by using the following formula
Midline:y = 3
Note, in the following equations that D = 3 = midliney = A (Bx+C) + D
y = -4 (2x + n) + 3
Also, the picture that is attached is what your equation looks like when graphed.
It would be 3.25 because you can’t round 0.001 up
The notation V(r) actually gives the volume of air inside the basketball. V(r) is volume as a function of radius, r It can be written as: V(r) = 4/3πr³ So, for any value of r, we can get the volume V. For, example, when r = 7cm we can say; V(7) = 4/3 x 22/7 x 7³ = 1437.33 cm³
Answer:
Step-by-step explanation:
That composite figure is made up of a square and a quarter of a circle. We will first find the area of the square. Then we will find the area of the circle and divide it by 4.
Area of square = 1.6 × 1.6
Area of square = 2.56 m squared
Area of circle = (3.14)(1.6²) In case you forgot, the area of a circle is A = πr².
Area of circle = 8.0384
Divide that by 4 to get 2.0096.
Add 2.0096 to 2.56 to get the total area, which is
4.5696 or 4.6 rounded (choice D)
Answer:
594 yd³
Step-by-step explanation:
11x9x6=594 yd³