I believe it would be -2 since you use rise over run. That would be -2/1
All you have to do is add 461 to 123 and it’s s=584
Answer:
-1 and -3
(n+7)(n-8)
Step-by-step explanation:
1. Find the Zeros
![f(x)=x^{2} +4x+3](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E%7B2%7D%20%2B4x%2B3)
![f(x)=\left(x+1\right)\left(x+3\right)](https://tex.z-dn.net/?f=f%28x%29%3D%5Cleft%28x%2B1%5Cright%29%5Cleft%28x%2B3%5Cright%29)
![x+1=0\\x=-1\\x+3=0\\x=-3](https://tex.z-dn.net/?f=x%2B1%3D0%5C%5Cx%3D-1%5C%5Cx%2B3%3D0%5C%5Cx%3D-3)
2. Factoring Trinomials
![f(x)=n^{2} -n-56](https://tex.z-dn.net/?f=f%28x%29%3Dn%5E%7B2%7D%20-n-56)
![f(x)=\left(n+7\right)\left(n-8\right)](https://tex.z-dn.net/?f=f%28x%29%3D%5Cleft%28n%2B7%5Cright%29%5Cleft%28n-8%5Cright%29)
![n+7=0\\n=-7\\n-8=0\\n=8](https://tex.z-dn.net/?f=n%2B7%3D0%5C%5Cn%3D-7%5C%5Cn-8%3D0%5C%5Cn%3D8)
Answer:
Area:702
perimeter: 114
Step-by-step explanation:
24x27=648
6x9=54
648+54=702
27+24+18+6+9+30=114
Hi!
To compare this two sets of data, you need to use a t-student test:
You have the following data:
-Monday n1=16; <span>x̄1=59,4 mph; s1=3,7 mph
-Wednesday n2=20; </span>x̄2=56,3 mph; s2=4,4 mph
You need to calculate the statistical t, and compare it with the value from tables. If the value you obtained is bigger than the tabulated one, there is a statistically significant difference between the two samples.
![t= \frac{X1-X2}{ \sqrt{ \frac{(n1-1)* s1^{2}+(n2-1)* s2^{2} }{n1+n2-2}} * \sqrt{ \frac{1}{n1}+ \frac{1}{n2}} } =2,2510](https://tex.z-dn.net/?f=t%3D%20%5Cfrac%7BX1-X2%7D%7B%20%5Csqrt%7B%20%5Cfrac%7B%28n1-1%29%2A%20s1%5E%7B2%7D%2B%28n2-1%29%2A%20s2%5E%7B2%7D%20%7D%7Bn1%2Bn2-2%7D%7D%20%2A%20%5Csqrt%7B%20%5Cfrac%7B1%7D%7Bn1%7D%2B%20%5Cfrac%7B1%7D%7Bn2%7D%7D%20%7D%20%3D2%2C2510)
To calculate the degrees of freedom you need to use the following equation:
![df= \frac{ (\frac{ s1^{2}}{n1} + \frac{ s2^{2}}{n2})^{2}}{ \frac{(s1^{2}/n1)^{2}}{n1-1}+ \frac{(s2^{2}/n2)^{2}}{n2-1}}=33,89](https://tex.z-dn.net/?f=df%3D%20%5Cfrac%7B%20%28%5Cfrac%7B%20s1%5E%7B2%7D%7D%7Bn1%7D%20%2B%20%5Cfrac%7B%20s2%5E%7B2%7D%7D%7Bn2%7D%29%5E%7B2%7D%7D%7B%20%5Cfrac%7B%28s1%5E%7B2%7D%2Fn1%29%5E%7B2%7D%7D%7Bn1-1%7D%2B%20%5Cfrac%7B%28s2%5E%7B2%7D%2Fn2%29%5E%7B2%7D%7D%7Bn2-1%7D%7D%3D33%2C89)
≈34
The tabulated value at 0,05 level (using two-tails, as the distribution is normal) is 2,03. https://www.danielsoper.com/statcalc/calculator.aspx?id=10
So, as the calculated value is higher than the critical tabulated one,
we can conclude that the average speed for all vehicles was higher on Monday than on Wednesday.