6.4 x 10^3 = 6400
1.4 x 10^4 = 14000
7.5 x 10^3 = 7500
total = 6400 + 14,000 + 7500
total = 27900 or 2.79 x 10^4 <===
Answer:
B
Step-by-step explanation:
look at where the line reaches on the y-axis
The given equation is ⇒⇒⇒ 2y - 4x = 6
∴ 2y = 4x + 6 ⇒ divide all the equation over 2
∴ y = 2x + 3 and it can be written as ⇒⇒⇒ y - 2x = 3
The last equation represents a straight line with a slope = 2 and y-intercept = 3
To construct a system of equations with definitely many solutions and the equation ( 2y-4x=6 ) is one of the equations, the other equation must have the same slope and the same y-intercept.
so, the general solution of the other equation is ⇒ a ( y - 2x ) = 3a
Where a is constant and belongs to R ( All real numbers )
The system of equations which has definitely many solutions is consisting of <u>Coincident lines.</u>
keeping in mind that anything raised at the 0 power, is 1, with the sole exception of 0 itself.
![\bf ~~~~~~~~~~~~\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} \qquad \qquad \cfrac{1}{a^n}\implies a^{-n} \qquad \qquad a^n\implies \cfrac{1}{a^{-n}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{(r^{-7}b^{-8})^0}{t^{-4}w}\implies \cfrac{1}{t^{-4}w}\implies \cfrac{1}{t^{-4}}\cdot \cfrac{1}{w}\implies t^4\cdot \cfrac{1}{w}\implies \cfrac{t^4}{w}](https://tex.z-dn.net/?f=%20%5Cbf%20~~~~~~~~~~~~%5Ctextit%7Bnegative%20exponents%7D%0A%5C%5C%5C%5C%0Aa%5E%7B-n%7D%20%5Cimplies%20%5Ccfrac%7B1%7D%7Ba%5En%7D%0A%5Cqquad%20%5Cqquad%0A%5Ccfrac%7B1%7D%7Ba%5En%7D%5Cimplies%20a%5E%7B-n%7D%0A%5Cqquad%20%5Cqquad%20a%5En%5Cimplies%20%5Ccfrac%7B1%7D%7Ba%5E%7B-n%7D%7D%0A%5C%5C%5C%5C%5B-0.35em%5D%0A%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%0A%5Ccfrac%7B%28r%5E%7B-7%7Db%5E%7B-8%7D%29%5E0%7D%7Bt%5E%7B-4%7Dw%7D%5Cimplies%20%5Ccfrac%7B1%7D%7Bt%5E%7B-4%7Dw%7D%5Cimplies%20%5Ccfrac%7B1%7D%7Bt%5E%7B-4%7D%7D%5Ccdot%20%5Ccfrac%7B1%7D%7Bw%7D%5Cimplies%20t%5E4%5Ccdot%20%5Ccfrac%7B1%7D%7Bw%7D%5Cimplies%20%5Ccfrac%7Bt%5E4%7D%7Bw%7D%20)
Abigail collected more, she collected 87.5 lb
they collected 107.5 pounds together
