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2 years ago

69. REAL-WORLD APPLICATIONS

Mathematics

1 answer:

svp [43]2 years ago

3 0

Answer:

Cost of per session the average rate is $45.

Step-by-step explanation:

It is given that a gym membership with two personal training session cost $125, while gym membership with five personal training sessions cost $260.

It is required to find what is the cost per session.

Step 1 of 1

It is given that a gym membership with two personal training session cost $125, while gym membership with five personal training sessions cost $260.

To find the cost of per session calculate the average rate.

Now let $f(x)$ be the cost per session use the for the average rate of change, and the input value is the number of personal traings x.

$m=\frac{f\left(x_{2}\right)-f\left(x_{1}\right)}{x_{2}-x_{1}}$$

Now substitute, $125 for $$f\left(x_{2}\right)$ , 260 for $f\left(x_{1}\right), 2$ for $x_{1}$ and 5 for $x_{2}$ then,

$m=\frac{260-125}{5-2}$\$$\begin{aligned}&=\frac{135}{3} \\&=45\end{aligned}$$

Cost of per session the average rate is $45.

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Let φ(x, y) = arctan (y/x) .

Alexandra [31]

Answer:

a) $\large F(x,y)=(-\frac{y}{x^2+y^2},\frac{x}{x^2+y^2})$

b) $\large \mathbb{R}^2-\{(0,0)\}$

c) the points of the form (x, -x) for x≠0

Step-by-step explanation:

If φ(x, y) = arctan (y/x), the vector field F = ∇φ would be

$\large F(x,y)=(\frac{\partial \phi}{\partial x},\frac{\partial \phi}{\partial y})$

On one hand we have,

$\large \frac{\partial \phi}{\partial x}=\frac{\partial arctan(y/x)}{\partial x}=\frac{-y/x^2}{1+(y/x)^2}=-\frac{y/x^2}{1+y^2/x^2}=\\\\=-\frac{y/x^2}{(x^2+y^2)/x^2}=-\frac{y}{x^2+y^2}$

On the other hand,

$\large \frac{\partial \phi}{\partial y}=\frac{\partial arctan(y/x)}{\partial y}=\frac{1/x}{1+(y/x)^2}=\frac{1/x}{1+y^2/x^2}=\\\\=\frac{1/x}{(x^2+y^2)/x^2}=\frac{x}{x^2+y^2}$

$\large F(x,y)=(-\frac{y}{x^2+y^2},\frac{x}{x^2+y^2})$

The domain of definition of F is

$\large \mathbb{R}^2-\{(0,0)\}$

i.e., all the plane X-Y except the (0,0)

Here we want to find all the points such that

$\large (-\frac{y}{x^2+y^2},\frac{x}{x^2+y^2})=(k,k)$

where k is a real number other than 0.

But this means

$\large -\frac{y}{x^2+y^2}=\frac{x}{x^2+y^2}\Rightarrow y=-x$

So, all the points in the line y = -x except (0,0) are parallel to the vector field F, that is, the points (x, -x) with x≠ 0

8 0

3 years ago

If the point (x, y) is on the y-axis, which of the following must be true? A). x=0 B). y=0

Musya8 [376]

Answer:

X = 0

Step-by-step explanation:

3 0

3 years ago

The driver of the bus filled the gas tank with gas by putting in 21 gallon. If the gas gauge was at five-eighths before she fill

vazorg [7]

Answer:

56 gallons

Step-by-step explanation:

When her gas tank is full, she has x gallons in the tank.

when she went to the gas station, she had (5/8) of x gallons of gas in her tank. she added 21 gallons into her tank, then she had x gallons in her tank.

(5/8)x + 21 = x

subtract x and 21 from both sides

(5/8)x - x = -21

factor out an x from the left side

x(5/8 - 1) = -21

simplify the parenthesis

x(-3/8) = -21

multiply both sides by -8/3

x= 56 gallons

8 0

4 years ago

Last Question<br> (You can ignore this sentence)

Harrizon [31]

3y-20+x+13=3x+9
3y-20+x+13+2y=180

3y-7+x=3x+9
3y=2x+16
y=2/3x+16/3

5y+x=187
5(2/3x+16/3)+x=187
10/3x+80/3+x=187
13/3x=481/3

x=37

5 0

3 years ago

209.106 in word form

Scrat [10]

In mathematics, number with a symbol of a point, is expressed in decimal form. When they are read, the numbers after the decimal point are read digit after digit. Therefore, in word form, the number is read as: Two hundred nine point one zero six.

8 0

4 years ago

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