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3 years ago

6

I need help on 24 please

1 answer:

dusya [7]3 years ago

4 0

Where's the table. you need it to answer the questions.

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Write 0.00005974 in scientific notation.

larisa86 [58]

Answer:

Step-by-step explanation:

For correct scientific notation, we need to have 1 number to the left of the decimal, and everything else to the right. Since our number is already less than 1, the exponent representing the number of places we move the decimal will be negative. We have to move the decimal 5 places to the right to get the 5 to the left of the decimal and everything else to the right, making this:

$5.974*10^{-5$

7 0

3 years ago

Read 2 more answers

7 pies shared by 9 people how much does each person get

WINSTONCH [101]

Answer: 0.77777777777 Pies

Step-by-step explanation: divide 7 by 9

8 0

3 years ago

A manufacturing plant earned \$80$80dollar sign, 80 per man-hour of labor when it opened. Each year, the plant earns an addition

Ksju [112]

Answer:

80(1+0.06)(1+0.06)(1+0.06)

4 0

2 years ago

Use the shell method to write and evaluate the definite integral that represents the volume of the solid generated by revolving

faust18 [17]

Answer:

$Volume = \frac{384}{7}\pi$

Step-by-step explanation:

Given (Missing Information):

$y = x^\frac{3}{2}$ ; $y = 8$ ; $x=0$

Required

Determine the volume

Using Shell Method:

$V = 2\pi \int\limits^a_b {p(y)h(y)} \, dy$

First solve for a and b.

$y = x^\frac{3}{2}$ and $y = 8$

Substitute 8 for y

$8 = x^\frac{3}{2}$

Take 2/3 root of both sides

$8^\frac{2}{3} = x^{\frac{3}{2}*\frac{2}{3}}$

$8^\frac{2}{3} = x$

$2^{3*\frac{2}{3}} = x$

$2^2 = x$

$4 =x$

$x = 4$

This implies that:

$a = 4$

For $x=0$

This implies that:

$b=0$

So, we have:

$V = 2\pi \int\limits^a_b {p(y)h(y)} \, dy$

$V = 2\pi \int\limits^4_0 {p(y)h(y)} \, dy$

The volume of the solid becomes:

$V = 2\pi \int\limits^4_0 {x(8 - x^{\frac{3}{2}}}) \, dx$

Open bracket

$V = 2\pi \int\limits^4_0 {8x - x.x^{\frac{3}{2}}} \, dx$

$V = 2\pi \int\limits^4_0 {8x - x^{\frac{2+3}{2}}} \, dx$

$V = 2\pi \int\limits^4_0 {8x - x^{\frac{5}{2}}} \, dx$

Integrate

$V = 2\pi * [{\frac{8x^2}{2} - \frac{x^{1+\frac{5}{2}}}{1+\frac{5}{2}}]\vert^4_0$

$V = 2\pi * [{4x^2 - \frac{x^{\frac{2+5}{2}}}{\frac{2+5}{2}}]\vert^4_0$

$V = 2\pi * [{4x^2 - \frac{x^{\frac{7}{2}}}{\frac{7}{2}}]\vert^4_0$

$V = 2\pi * [{4x^2 - \frac{2}{7}x^{\frac{7}{2}}]\vert^4_0$

Substitute 4 and 0 for x

$V = 2\pi * ([{4*4^2 - \frac{2}{7}*4^{\frac{7}{2}}] - [{4*0^2 - \frac{2}{7}*0^{\frac{7}{2}}])$

$V = 2\pi * ([{4*4^2 - \frac{2}{7}*4^{\frac{7}{2}}] - [0])$

$V = 2\pi * [{4*4^2 - \frac{2}{7}*4^{\frac{7}{2}}]$

$V = 2\pi * [{64 - \frac{2}{7}*2^2^{*\frac{7}{2}}]$

$V = 2\pi * [{64 - \frac{2}{7}*2^7]$

$V = 2\pi * [{64 - \frac{2}{7}*128]$

$V = 2\pi * [{64 - \frac{2*128}{7}]$

$V = 2\pi * [{64 - \frac{256}{7}]$

Take LCM

$V = 2\pi * [\frac{64*7-256}{7}]$

$V = 2\pi * [\frac{448-256}{7}]$

$V = 2\pi * [\frac{192}{7}]$

$V = [\frac{2\pi * 192}{7}]$

$V = \frac{\pi * 384}{7}$

$V = \frac{384}{7}\pi$

Hence, the required volume is:

$Volume = \frac{384}{7}\pi$

3 0

2 years ago

ach light bulb at Hotel California is either incandescent or fluorescent. At a certain moment, forty percent of the incandescent

Trava [24]

Answer:

10%

Step-by-step explanation:

The computation of the percentage of bulbs that switched on incandescent is as follows;

Let us assume the incandescent be I

And, the fluorescent be F

Now the equation is

0.4I + 0.9F = 0.8 (I+F)

0.41I + 0.9F = 0.8I + 0.8F

So here

0.4I = 0.1F

Now the percentage would be for incandescent in the case of switched on is

= 0.4I ÷ 0.8(I+F) × 100

= 0.1F ÷ 1F

= 10%

6 0

3 years ago