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maw [93]
2 years ago
11

Is the sequence 1, 5, 9, 13, 17, 21, ... arithmetic? If so, find the common difference. /(5 pts)

Mathematics
2 answers:
VikaD [51]2 years ago
7 0

Answer:

Common difference is 4

Step-by-step explanation:

25 , 29, 33,37,41

zalisa [80]2 years ago
3 0

Answer: yes it is a arithmetic sequence  4 is the common difference

Step-by-step explanation: hope it helps

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For the polynomial function ƒ(x) = −x6 + 3 x4 + 4x2, find the zeros. Then determine the multiplicity at each zero and state whet
alisha [4.7K]
I believe the answer is 6
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3 years ago
X – y = 2<br>3x + y = 10<br><br>all of yalls answer r wrong the answer is x= 3 and y= 1 ​
Y_Kistochka [10]

Answer:

Step-by-step explanation:

People always get it wrong just for points

3 0
3 years ago
I'LL GIVE BRAINLIEST !!! FASTER<br><br>please explain how do you get the answer !​
aliya0001 [1]

Answer:

70

Step-by-step explanation:

we have the angle of vertex in the isosceles triangle = 180-2*bottom coner= 180-65/2=50

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7 0
3 years ago
Read 2 more answers
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Temka [501]

Step-by-step explanation:

I think 360-175 iam not sure

4 0
3 years ago
Find a set of vectors {u⃗ ,v⃗ }{u→,v→} in r4r4 that spans the solution set of the equations {w−x+2y+4z5w+2x−y+3z==0,0. {w−x+2y+4
rusak2 [61]
Given

w-x+2y+4z=0 \\ 5w+2x-y+3z=0

We can rewrite it in matrix form as:

\left[\begin{array}{cccc}1&-1&2&4\\5&2&-1&3\\0&0&0&0\\0&0&0&0\end{array}\right]   \left[\begin{array}{c}w\\x\\y\\z\end{array}\right] =\left[\begin{array}{c}0\\0\\0\\0\end{array}\right] \\  \\ \left[\begin{array}{cccc}1&-1&2&4\\5&2&-1&3\\0&0&0&0\\0&0&0&0\end{array}\right|\left.\begin{array}{c}0\\0\\0\\0\end{array}\right]\ \ \ \ \ -5R_1+R_2\rightarrow R_2
\left[\begin{array}{cccc}1&-1&2&4\\0&7&-11&-17\\0&0&0&0\\0&0&0&0\end{array}\right|\left.\begin{array}{c}0\\0\\0\\0\end{array}\right]\ \ \ \ \  \frac{1}{7} R_2\rightarrow R_2 \\  \\ \left[\begin{array}{cccc}1&-1&2&4\\0&1&-\frac{11}{7}&-\frac{17}{7}\\0&0&0&0\\0&0&0&0\end{array}\right|\left.\begin{array}{c}0\\0\\0\\0\end{array}\right]\ \ \ \ \ R_1+R_2\rightarrow R_1
\\  \\ \left[\begin{array}{cccc}1&0&\frac{3}{7}&\frac{11}{7}\\0&1&-\frac{11}{7}&-\frac{17}{7}\\0&0&0&0\\0&0&0&0\end{array}\right|\left.\begin{array}{c}0\\0\\0\\0\end{array}\right] \\  \\ \Rightarrow w= -\frac{3}{7} y- \frac{11}{7} z \\ x=\frac{11}{7} y+ \frac{17}{7} z \\ y=free \\ z=free \\  \\ =y\left\ \textless \ -\frac{3}{7},\frac{11}{7}1,0\right\ \textgreater \ +z\left\ \textless \ - \frac{11}{7},\frac{17}{7},0,1\right\ \textgreater \

Thus, the solution set is a span of \{\left\ \textless \ -\frac{3}{7},\frac{11}{7}1,0\right\ \textgreater \ ,\left\ \textless \ - \frac{11}{7},\frac{17}{7},0,1\right\ \textgreater \ \}
7 0
3 years ago
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