Answer:

The farthest point is the Challenger Deep
Step-by-step explanation:
Given


Solving (a): The sea level
Both elevations had signs in front of them.
The sea level is the point at the neutral level, neither positive nor negative.
Hence:

Solving (b): Farthest Point.
The farthest point is the one with the highest magnitude.
Comparing
to 
-35,797 ft has the highest magnitude.
Hence:
<em>The farthest point is the Challenger Deep</em>
120% of 12 is 14.4.I got this by doing this:
12/x=100/120
<span>(12/x)*x=(100/120)*x - </span>we multiply both sides of the equation by x
<span>12=0.833333333333*x - </span>we divide both sides of the equation by (0.833333333333) to get x
<span>12/0.833333333333=x </span>
<span>14.4=x </span>
<span>x=14.4</span>
The volume of a square pyramid is (1/3)(area of base)(height of pyramid).
Here the area of the base is (10 ft)^2 = 100 ft^2.
13 ft is the height of one of the triangular sides, but not the height of the pyramid. To find the latter, draw another triangle whose upper vertex is connected to the middle of one of the four equal sides of the base by a diagonal of length 13 ft. That "middle" is 5 units straight down from the upper vertex. Thus, you have a triangle with known hypotenuse (13 ft) and known opposite side 5 feet (half of 10 ft). What is the height of the pyramid?
To find this, use the Pyth. Thm.: (5 ft)^2 + y^2 = (13 ft)^2. y = 12 ft.
Then the vol. of the pyramid is (1/3)(area of base)(height of pyramid) =
(1/3)(100 ft^2)(12 ft) = 400 ft^3 (answer)
Answer:
80%
Step-by-step explanation:
75% + 20% - 15% = 80%
The probability is 80%
Answer:
The distance between the cruise ship and the sail boat is 517 feet.
Step-by-step explanation:
The cruise ship is 236 feet tall, and the sailboat is 236 tall; this means the distance between the top of the cruise ship and the top of the sail boat is
236 feet - 27 feet = 209 feet.
We also know that the angel of depression from the top of the cruise ship to the bottom of the cruise ship is 22°. This forms a right triangle as shown in the figure attached.
Now from trigonometry we get:



The distance between the cruise ship and the sailboat is 517 feet.