To write 8.57 as a fraction you have to write 8.57 as numerator and put 1 as the denominator. Now you multiply numerator and denominator by 10 as long as you get in numerator the whole number.
8.57 = 8.57/1 = 85.7/10 = 857/100
And finally we have:
8.57 as a fraction equals 857/100
ANSWER

EXPLANATION
The given binomial expansion is:

Compare this to

we have a=2x , b=-3y and n=10
We want to find the coefficient of the term

This implies that, r=5.
The terms in the expansion can be obtained using

We substitute the given values to obtain;



Hence the coefficient is;

brainly being slow today so i did my work on this attachment
╦────────────────────────────╦
│Hope this helped _____________________│
│~Xxxtentaction _______________________│
╩__________________________________╩
Answer:
-15626
you just multiply -5 by itself 6 times
Step-by-step explanation:
Answer:

Step-by-step explanation:
Coordinates of Point b
b lies on the circle whose equation is 

Comparing with the general form a circle with center at the origin: 
The radius of the circle =17 which is the length of the hypotenuse of the terminal ray through point b.
For an angle drawn in standard position through point b,
x=-8 which is negative
y=15 which is positive
Therefore, the angle is in Quadrant II.
