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elena-s [515]
3 years ago
11

3 square roots 7 multiplied by square root of 7 / 6 square roots of 7 raised to the 5

Mathematics
2 answers:
mojhsa [17]3 years ago
5 0
98 is what it’s round too
kodGreya [7K]3 years ago
3 0
Approximately 97.6149
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11. In a parking garage there is a 6:5 ratio of blue cars to
oksian1 [2.3K]
Answer: 125 Red Cars

6:5 = 275; Write as equation by adding a variable to the ratio:

6x + 5x = 275; add
11x = 275; divide
x = 25; put 25 in for “5x,” which represents the ratio 5 for red cars

5(x) = 5(25) = 125

Check:
6(25) + 5(25) = 275; multiply
150 + 125 = 275; add
275 = 275; is true so answer is right.
6 0
2 years ago
Drew is holding a fund-raiser. He is taking donations from his family members to supports a charity. Each family member donates
larisa86 [58]

They each give $10 because the pattern is changing by 10.

7 0
3 years ago
May someone please help me with question 6 and 7?
svetlana [45]
Lowest wind chill temperature on Monday was 1/4(-36) = -9 F

The lakes initial level with respect of normal is -8 inches
New level after decreases = -8 - 1 1/4 - 2 3/8 = -11 5/8 inches.
5 0
3 years ago
The answer to this problem?
LenaWriter [7]

The simplified expression of \sqrt{\frac{162x^9}{2x^{27}}} is \frac{9}{x^9}

<h3>How to simplify the expression?</h3>

The expression is given as:

\sqrt{\frac{162x^9}{2x^{27}}}

Divide 162 and 2 by 2

\sqrt{\frac{81x^9}{x^{27}}}

Take the square root of 81

9\sqrt{\frac{x^9}{x^{27}}}

Apply the quotient rule of indices

9\sqrt{\frac{1}{x^{27-9}}}

Evaluate the difference

9\sqrt{\frac{1}{x^{18}}}

Take the square root of x^18

\frac{9}{x^9}

Hence, the simplified expression of \sqrt{\frac{162x^9}{2x^{27}}} is \frac{9}{x^9}

Read more about expressions at:

brainly.com/question/723406

#SPJ1

5 0
2 years ago
Which property of operation could you use to show whether 7y + 7b + 3y and 7(y x b) + 3b are equivalent or not
Dmitry_Shevchenko [17]

Answer and explanation:

They are not equivalent because if we simplify the second expression, the result isn't the same:

7(y×b)+3b

= 7(yb)+3b

=7yb + 3b

Therefore 7yb+3b≠7y+7b+3y

And even though you meant

7(y+b)+3b

=7y+7b+3b

=7y+10b

7y+10b≠10y+7b

5 0
2 years ago
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