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elena-s [515]
3 years ago
11

3 square roots 7 multiplied by square root of 7 / 6 square roots of 7 raised to the 5

Mathematics
2 answers:
mojhsa [17]3 years ago
5 0
98 is what it’s round too
kodGreya [7K]3 years ago
3 0
Approximately 97.6149
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Simplify the radical expression63x^15y^9/7xy^11
Andre45 [30]
Are the 63x and the y being added or multiplied?

3 0
3 years ago
A survey of 160 students is taken to determine whether they play sports and whether they have a job. Of the 71 students who play
Iteru [2.4K]

Answer:

The answer is 44- so B

Step-by-step explanation:

I did the quiz, and that was the correct answer.  ( Also I took this on goformative.)

3 0
3 years ago
Assume that a randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of
jarptica [38.1K]

Answer:

The "probability that a given score is less than negative 0.84" is  \\ P(z.

Step-by-step explanation:

From the question, we have:

  • The random variable is <em>normally distributed</em> according to a <em>standard normal distribution</em>, that is, a normal distribution with \\ \mu = 0 and \\ \sigma = 1.
  • We are provided with a <em>z-score</em> of -0.84 or \\ z = -0.84.

Preliminaries

A z-score is a standardized value, i.e., one that we can obtain using the next formula:

\\ z = \frac{x - \mu}{\sigma} [1]

Where

  • <em>x</em> is the <em>raw value</em> coming from a normal distribution that we want to standardize.
  • And we already know that \\ \mu and \\ \sigma are the mean and the standard deviation, respectively, of the <em>normal distribution</em>.

A <em>z-score</em> represents the <em>distance</em> from \\ \mu in <em>standard deviations</em> units. When the value for z is <em>negative</em>, it "tells us" that the raw score is <em>below</em> \\ \mu. Conversely, when the z-score is <em>positive</em>, the standardized raw score, <em>x</em>, is <em>above</em> the mean, \\ \mu.

Solving the question

We already know that \\ z = -0.84 or that the standardized value for a raw score, <em>x</em>, is <em>below</em> \\ \mu in <em>0.84 standard deviations</em>.

The values for probabilities of the <em>standard normal distribution</em> are tabulated in the <em>standard normal table, </em>which is available in Statistics books or on the Internet and is generally in <em>cumulative probabilities</em> from <em>negative infinity</em>, - \\ \infty, to the z-score of interest.

Well, to solve the question, we need to consult the <em>standard normal table </em>for \\ z = -0.84. For this:

  • Find the <em>cumulative standard normal table.</em>
  • In the first column of the table, use -0.8 as an entry.
  • Then, using the first row of the table, find -0.04 (which determines the second decimal place for the z-score.)
  • The intersection of these two numbers "gives us" the cumulative probability for z or \\ P(z.

Therefore, we obtain \\ P(z for this z-score, or a slightly more than 20% (20.045%) for the "probability that a given score is less than negative 0.84".

This represent the area under the <em>standard normal distribution</em>, \\ N(0,1), at the <em>left</em> of <em>z = -0.84</em>.

To "draw a sketch of the region", we need to draw a normal distribution <em>(symmetrical bell-shaped distribution)</em>, with mean that equals 0 at the middle of the distribution, \\ \mu = 0, and a standard deviation that equals 1, \\ \sigma = 1.

Then, divide the abscissas axis (horizontal axis) into <em>equal parts</em> of <em>one standard deviation</em> from the mean to the left (negative z-scores), and from the mean to the right (positive z-scores).  

Find the place where z = -0.84 (i.e, below the mean and near to negative one standard deviation, \\ -\sigma, from it). All the area to the left of this value must be shaded because it represents \\ P(z and that is it.

The below graph shows the shaded area (in blue) for \\ P(z for \\ N(0,1).

7 0
3 years ago
A rectangle has a perimeter of 84 meters and a length of 35 meters. What is the width of the rectangle?
BaLLatris [955]
To find the perimeter of a rectangle, we can use this formula: 2L + 2W
Where L is the length and W is the width.

We know the perimeter and we know the length and we want to find the width.
Substitute the values back into the formula.

2(35) + 2W = 84
70 + 2W = 84
2W = 14 <-- Subtract both sides by 70
W = 7 <-- Divide both sides by 2

So, width is 7 meters long.

8 0
3 years ago
Read 2 more answers
SOMEOME HELP this is my third time posting those SERIOUSLY HELP ME PLEASE
Hoochie [10]

The correct answer is C (7, 9)

Firstly we know that each point is 6 away from the other in terms of x and in terms of y. Now we also know that for every 6, we will be one away from point B and five away from point A. We know this because the ratio is AB 5:1, meaning that the 5 is on the A side (they both come first).

So, we can just add 5 to each of the A value numbers to get point P.

A = (2, 4)

P = (2+5, 4+5)

P = (7, 9)

6 0
3 years ago
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