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tatiyna
2 years ago
12

((sinB)/1+cosB) + ((1+cosB)/sinB) = 2cscB prove that the equation is an identity

Mathematics
1 answer:
Contact [7]2 years ago
4 0

Step-by-step explanation:

If you need any explanation, we can communicate normally

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A basketball player makes 17 of the 25 shots she takes. What percentage of shots did she successfully make?
Mumz [18]
Percentage of successful shots = 14/25 x 100 = 56%

Answer: 56%
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The length of a rectangle is 3 times the width. The perimeter is 96m. What is the length
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Length =3×12 =36 m.

8 0
3 years ago
Suppose that 30% of a population carries a certain gene. You want to estimate the probability that it will take at least a sampl
VMariaS [17]

Answer:

A

Step-by-step explanation:

Since only 30% of the population carries the gene, that would mean 70% doesn't carry it. Since you are using 10 digits for this experiment (0-9) this would mean that 0-2 would carry the gene (this equals 30%) and 3-9 would not (70%)

6 0
3 years ago
Please answer all please​
Firdavs [7]

Answer:

Step-by-step explanation:

The first parabola has vertex (-1, 0) and y-intercept (0, 1).

We plug these values into the given vertex form equation of a parabola:

y - k = a(x - h)^2 becomes

y - 0 = a(x + 1)^2

Next, we subst. the coordinates of the y-intercept (0, 1) into the above, obtaining:

1 = a(0 + 1)^2, and from this we know that a = 1.  Thus, the equation of the first parabola is

y = (x + 1)^2

Second parabola:  We follow essentially the same approach.  Identify the vertex and the two horizontal intercepts.  They are:

vertex:  (1, 4)

x-intercepts:  (-1, 0) and (3, 0)

Subbing these values into y - k = a(x - h)^2, we obtain:

                                            0 - 4 = a(3 - 1)^2, or

                                                -4 = a(2)².  This yields a = -1.

Then the desired equation of the parabola is

y - 4 = -(x - 1)^2

7 0
3 years ago
Find the derivative of the function. y = sin−1(6x + 1)
liraira [26]

If you don't know the derivative of the inverse of sine, you can use implicit differentiation. Apply sine to both sides:

y=\sin^{-1}(6x+1)\implies\sin y=6x+1

(true for <em>y</em> between -π/2 and π/2)

Now take the derivative of both sides and solve for it:

\cos y\dfrac{\mathrm dy}{\mathrm dx}=6

\dfrac{\mathrm dy}{\mathrm dx}=6\sec y

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac6{\cos\left(\sin^{-1}(6x+1)\right)}

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac6{\sqrt{1-(6x+1)^2}}

7 0
3 years ago
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