I think the best possibility that could lead Aiden's mistake are the following, First, it must be that the length of the paper strips are not the same. Second, it would be that she miscounted the strips. I hope you are satisfied with my answer and feel free to ask for more
Sides FH and HJ are not congruent
Step-by-step explanation:
The equation of a circle can be the expanded form of
\large \text{$(x-a)^2+(y-b)^2=r^2$}(x−a)
2
+(y−b)
2
=r
2
where rr is the radius of the circle, (a,\ b)(a, b) is the center of the circle, and (x,\ y)(x, y) is a point on the circle.
Here, the equation of the circle is,
\begin{gathered}\begin{aligned}&x^2+y^2+10x-4y-20&=&\ \ 0\\ \\ \Longrightarrow\ \ &x^2+y^2+10x-4y+25+4-49&=&\ \ 0\\ \\ \Longrightarrow\ \ &x^2+y^2+10x-4y+25+4&=&\ \ 49\\ \\ \Longrightarrow\ \ &x^2+10x+25+y^2-4y+4&=&\ \ 49\\ \\ \Longrightarrow\ \ &(x+5)^2+(y-2)^2&=&\ \ 7^2\end{aligned}\end{gathered}
⟹
⟹
⟹
⟹
x
2
+y
2
+10x−4y−20
x
2
+y
2
+10x−4y+25+4−49
x
2
+y
2
+10x−4y+25+4
x
2
+10x+25+y
2
−4y+4
(x+5)
2
+(y−2)
2
=
=
=
=
=
0
0
49
49
7
2
From this, we get two things:
\begin{gathered}\begin{aligned}1.&\ \ \textsf{Center of the circle is $(-5,\ 2)$.}\\ \\ 2.&\ \ \textsf{Radius of the circle is $\bold{7}$ units. }\end{aligned}\end{gathered}
1.
2.
Center of the circle is (−5, 2).
Radius of the circle is 7 units.
Hence the radius is 7 units.
Hello!
We are given the weight of Mia's dog and told to find the weight of Lettie's dog based on the known relationship. Using these given values, we can create the following equation (let "w" represent the total weight of Lettie's dog):
w = 32.6(3.8)
Simplify the right side of the equation:
w = 123.88
We have now proven that Lettie's dog weighs 123.88 lbs.
I hope this helps!
Since there are 12 months in there year and there have already been 3 months there are 9 left
we need to multiply 4.25 by 9 and then add the first 15 inchess
4.25 times 9 = 38.25+15 = 53.25
Florida will recieve 53.25 inches of rain
I hope I've helped!
