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bogdanovich [222]
3 years ago
11

Find the midpoint of the segment with the given endpoints. (-10,10) and (-9,6)

Mathematics
1 answer:
Ad libitum [116K]3 years ago
3 0

Answer:

The answer is

<h2>( -  \frac{19}{2}  \: , \: 2)</h2>

Step-by-step explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

<h3>M = ( \frac{x1 + x2}{2}  , \:  \frac{y1 + y2}{2} )</h3>

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(-10,10) and (-9,6)

The midpoint is

<h3>M = ( \frac{ - 10 - 9}{2}  , \:  \frac{10 - 6}{2} ) \\  = ( -  \frac{19}{2}  \: , \:  \frac{4}{2} )</h3>

We have the final answer as

<h3>( -  \frac{19}{2}  \: , \: 2)</h3>

Hope this helps you

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The perimeter of a rectangle is 160 meters. The length is 20 meters greater than the width. Find the dimensions of the rectangle
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4 years ago
The sum of 27 and 4 times a number is three times the same number
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Answer:

x=-27

Step-by-step explanation:

27+4x=3x

So 27=-x

x=-27

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2 years ago
One angle of a triangle measures 110°. The other two angles are in a ratio of 3:4. What are the measures of those two angles?
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3 years ago
What is the binomial expansion of (2x-3)^5
faltersainse [42]

Answer:

(2x - 3)⁵= 32x⁵ - 240x⁴ + 720x³ - 1080x² + 810x - 243

Step-by-step explanation:

We need to write the expansion of Binomial (2x - 3)⁵

Here general form of binomial expansion is:

(a + b)ⁿ = ⁿC₀aⁿ + ⁿC₁aⁿ⁻¹b + ⁿC₂aⁿ⁻²b² + ⁿC₃aⁿ⁻³b³ + ... + ⁿCₙbⁿ

(2x - 3)⁵= ⁵C₀(2x)⁵ + ⁵C₁(2x)⁵⁻¹(-3) + ⁵C₂(2x)⁵⁻²(-3)² + ⁵C₃(2x)⁵⁻³(-3)³  

                +⁵C₄(2x)⁵⁻⁴(-3)⁴ + ⁵C₅(2x)⁵⁻⁵(-3)⁵

(2x - 3)⁵= (32x⁵) + 5(16x⁴)(-3) + 10(8x³)(-3)² + 10(4x²)(- 3)³ + 5(2x)(-3)⁴+(-3)⁵

(2x - 3)⁵= 32x⁵ - 240x⁴ + 720x³ - 1080x² + 810x - 243                

That's the final answer.

5 0
3 years ago
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