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snow_tiger [21]
3 years ago
15

What is 75% of 24? Thanks!

Mathematics
2 answers:
FrozenT [24]3 years ago
5 0
18 i looked it up hope its right 

Mice21 [21]3 years ago
4 0
The answer is 18. I hope I helped

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Which number produces a rational number when added to 1/2
JulijaS [17]

Answer:

C.   0.314.

Step-by-step explanation:

1/2 is rational. The answer is another rational number.

The only rational number in the list is 0.314.

3 0
2 years ago
Read 2 more answers
The hawks soccer team won 12 out of 14 games. If this rate continues, how many games will they win if they play a total of 21 ga
Schach [20]
1) 12 out of 14 = 85% Win Rate
2) Now you have to figure out what is 85% of 21 so you have to plug in what you have ? out of 21 = .85
3) Multiply 21 x .85 
4) Answer is They will win 18 out of 21 games


8 0
2 years ago
EXPERTS/ACE/GENIUSES
Naddik [55]

1SF = 1 1/2 = 1.5
centered at origin

answer is 
figures MNO and PNQ
6 0
3 years ago
This is from Khan academy I have to attach a PNG if you can help me solve it! Thank you!
Mekhanik [1.2K]

49^2m-m : Not equivalent

7^2m-2m : Not equivalent

7^2m-m : Not equivalent

This is actually a trick question. All of the following are actually false statements. Want to know why? Let me show you.

For exponents, if you are dividing a number to some power (i.e 5^3) by the SAME number to a different power (i.e 5^2), then the expression is 5^3-2 or 5^1 = 5. This is true for any number a such that a^b ÷ a^c = a^b-c.

Since 7 and 49 are not the same number, this rule does not apply and thus cannot be simplified any further.

Let me prove why. 5^3 = 125, and 5^2 = 25, and 125 ÷ 25 = 5. This is also the same as 5^3-2 = 5^1 = 5. We just proved this as so.

But, what about 7 and 49, or 2 different numbers. Well it doesn't apply. 7^3 = 343, and 49^2 = 2401, and 343 ÷ 2401 ≈ 0.14. Thus, this is NOT equal to 7^3-2 which is 7. We just proved that a^y ÷ b^z ≠ a^y-z. Congratulations!

Hope this helped!

7 0
1 year ago
Tickets to a school production cost $5 for a student ticket and $10 for an adult ticket. A total of 67 tickets were purchased at
podryga [215]
I cannot see the table, but there would be 56 student tickets and 21 adult tickets. You can find this by setting up both a cost equation and a total tickets equation. 
4 0
3 years ago
Read 2 more answers
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