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3 years ago

Brainliest for correct answer asap

Mathematics

2 answers:

Nutka1998 [239]3 years ago

8 0

Answer:

its the first one. Times the bigger numbers and add the indices. so it 16^7

vladimir2022 [97]3 years ago

5 0

Answer: A 16(7)

Step-by-step explanation:

First you multiply your base numbers,[4x4] to get 16 then you add your exponents [2+5] to get 7 and remember you can only add exponents not multiply them.

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Find the value of this expression if x = -9. x2 + 3 x +6

iren [92.7K]

Answer:

Step-by-step explanation:

x² + 3 = (-9)² + 3 { (-9)² = -9 *-9 = 81}

= 81 + 3

= 84

x + 6 = -9 + 6 = -3

7 0

3 years ago

Question 4 of 10

ludmilkaskok [199]

Answer:

Option C. 3√3

Step-by-step explanation:

Please see attached photo for brief explanation.

In the attached photo, we obtained the following:

Opposite = a

Adjacent = 3

Hypothenus = 6

Angle θ = 60°

We can obtain the value of 'a' as follow:

Tan θ = Opposite /Adjacent

Tan 60° = a/3

Cross multiply

a = 3 x Tan 60°

But: Tan 60° = √3

a = 3 x Tan 60°

a = 3 x √3

a = 3√3

Therefore, the length of the altitude of the equilateral triangle is 3√3.

5 0

3 years ago

Someone help, please and thank you

taurus [48]

Answer:

6√2

Step-by-step explanation:

Given,

θ = 45

Opposite side = 6

To find : - Hypotenuse

Formula : -

sin θ = Opposite side / Hypotenuse

[ The value of sin 45 = 1 / √2 ]

sin 45 = 6 / Hypotenuse

1 / √2 = 6 / Hypotenuse

Cross multiply,

Hypotenuse = 6√2

8 0

2 years ago

Read 2 more answers

Is 2/1/2 greater then 2/3/5

zavuch27 [327]

Answer: yes you are correct 2 /1/2 is greater

Step-by-step explanation:

7 0

3 years ago

Find the mass and center of mass of the lamina that occupies the region D and has the given density function rho. D is the trian

Alla [95]

Answer: mass (m) = 4 kg

center of mass coordinate: (15.75,4.5)

Step-by-step explanation: As a surface, a lamina has 2 dimensions (x,y) and a density function.

The region D is shown in the attachment.

From the image of the triangle, lamina is limited at x-axis: 0≤x≤2

At y-axis, it is limited by the lines formed between (0,0) and (2,1) and (2,1) and (0.3):

Points (0,0) and (2,1):

y = $\frac{1-0}{2-0}(x-0)$

y = $\frac{x}{2}$

Points (2,1) and (0,3):

y = $\frac{3-1}{0-2}(x-0) + 3$

y = -x + 3

Now, find total mass, which is given by the formula:

$m = \int\limits^a_b {\int\limits^a_b {\rho(x,y)} \, dA }$

Calculating for the limits above:

$m = \int\limits^2_0 {\int\limits^a_\frac{x}{2} {2(x+y)} \, dy \, dx }$

where a = -x+3

$m = 2.\int\limits^2_0 {\int\limits^a_\frac{x}{2} {(xy+\frac{y^{2}}{2} )} \, dx }$

$m = 2.\int\limits^2_0 {(-x^{2}-\frac{x^{2}}{2}+3x )} \, dx }$

$m = 2.\int\limits^2_0 {(\frac{-3x^{2}}{2}+3x)} \, dx }$

$m = 2.(\frac{-3.2^{2}}{2}+3.2-0)$

m = 2(-4+6)

m = 4

Mass of the lamina that occupies region D is 4.

Center of mass is the point of gravity of an object if it is in an uniform gravitational field. For the lamina, or any other 2 dimensional object, center of mass is calculated by:

$M_{x} = \int\limits^a_b {\int\limits^a_b {y.\rho(x,y)} \, dA }$